How many grams are there in 3.3 moles of potassium sulfide?
3.3 moles of potassium sulfide is equal to 363,86 g.
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
He formula for potassium dichromate is KËÃCrËÃOËÈ How many grams of oxygen will be in 2 moles of potassium dichromate?
The formula for potassium dichromate is K2Cr2O7 How many grams of oxygen will be in 2 moles of potassium dichromate?
How many grams of iron II sulfide have to react with hydrochloric acid to generate 12 g of hydrogen sulfide?
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
Molarity = moles of solute/Liters of solution ( 100 mL = 0.1 Liters) Moles of solute (K2SO4) = Liters of solution * Molarity Moles K2SO4 = 0.1 Liters * 0.1 M = 0.01 moles K2SO4 (174.27 grams/1 mole K2SO4) = 1.7 grams potassium sulfate =======================Add that many grams potassium sulfate to your 100 mL.