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To find the number of molecules in 122 grams of Cu(NO3)2, we need to first calculate the molar mass of Cu(NO3)2. The molar mass of Cu(NO3)2 is approximately 187.55 g/mol. Next, we convert the given mass to moles using the molar mass. Finally, we use Avogadro's number (6.022 x 10^23) to find the number of molecules, which would be approximately 3.25 x 10^22 molecules.
There are 2.76 grams of nitrogen in 7.5g of Ca(NO3)2.
To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.
Among the molecules NO, NO2, and NO3, NO3 will have the longest nitrogen-oxygen bond.
Among the molecules or ions NO, NO2, and NO3, the molecule with the strongest nitrogen-oxygen bond is NO3.
To find the number of molecules in 122 grams of Cu(NO3)2, we need to first calculate the molar mass of Cu(NO3)2. The molar mass of Cu(NO3)2 is approximately 187.55 g/mol. Next, we convert the given mass to moles using the molar mass. Finally, we use Avogadro's number (6.022 x 10^23) to find the number of molecules, which would be approximately 3.25 x 10^22 molecules.
There are 2.76 grams of nitrogen in 7.5g of Ca(NO3)2.
The number of molecules is 12,044280.10e23.
To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.
Among the molecules NO, NO2, and NO3, NO3 will have the longest nitrogen-oxygen bond.
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
Among the molecules or ions NO, NO2, and NO3, the molecule with the strongest nitrogen-oxygen bond is NO3.
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
For this you need the atomic (molecular) mass of Hg(NO3)2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Hg(NO3)2=324.6 grams8.50 grams Hg(NO3)2 / (324.6 grams) = .0262 moles Hg(NO3)2
Ca(NO3)2Number of atoms in the compound:Ca- 1N- 2O- 6Find the atomic masses of all atoms and add:Ca = 40.1N = 2 * 14.0 = 28.0O = 6 * 16.0 = 96.0___________________164.1 gEquation:# moles * added atomic mass = # gramsAnswer:4.2 moles * (164.1 g) = 689.22 grams of Ca(NO3)2
Increasing the temperature of the solution allowed more of the solute (NO3) to dissolve due to an increase in solubility. As temperature increases, the kinetic energy of the solvent molecules also increases, making it easier for the solute molecules to break apart and dissolve. At 55°C, the solubility of the compound was high enough to dissolve the extra 5 grams that initially settled out at 25°C.
To determine the grams of Cr(NO3)3 needed, first calculate the molar mass of Cr(NO3)3. Then, use the formula: moles = Molarity x Volume (in L) to find the moles of Cr(NO3)3. Finally, multiply the moles by the molar mass to get the grams.