i have 200 hp motor what i need cable size in 100 feet distance
746 Watts per horsepower / 480 volts x power factor x efficiency x 1.73 = amps assuming that the motor is three phase. 746 x 60 =44760 watts divided by 480 x 1.73 = 53.9 amps ( If the pf and eff. information is not known this will put you in the ball park)
It could be a single phase 1/4 HP motor running on 230 volts AC.
To answer this question, wire size is rated in the amount of amperage that it can legally carry. The formula to find amperage when the HP is known is I = HP x 746/1.73 x E x %eff x pf. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. Amps = 30 x 746 = 22380 = 22380/ 1.73 x 480 x .87 x .87 = 22380/629 = 35.6 amps. The electrical code states that a motor conductor has to be rated at 125% of the motors full load amperage. 35.6 x 125% = 44.5 A #8 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 50 and 55 amps respectively.
Wire is sized by the load amperage. The formula for amperage when the HP is known is I = HP x 746/1.73 x E X %eff x pf. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. I = 60 x 746 = 44760/ 1.73 x 480 x .89 x .89 = 44760/658 = 68 amps. Motor feeders have to be sized to 125% of the motors full load amps. 68 x 125% = 85 amps A #3 copper conductor will limit the voltage drop to3% or less when supplying 85 amps for 220 feet on a 480 volt system.
i have 200 hp motor what i need cable size in 100 feet distance
The maximum single phase HP motor listed in the CEC is 10 HP. At 115 volts 100 amps and 230 volts 50 amps.
what is the full load amps for 2.4 hp motor at 460 volts ?
746 Watts per horsepower / 480 volts x power factor x efficiency x 1.73 = amps assuming that the motor is three phase. 746 x 60 =44760 watts divided by 480 x 1.73 = 53.9 amps ( If the pf and eff. information is not known this will put you in the ball park)
It could be a single phase 1/4 HP motor running on 230 volts AC.
To answer this question, wire size is rated in the amount of amperage that it can legally carry. The formula to find amperage when the HP is known is I = HP x 746/1.73 x E x %eff x pf. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. Amps = 30 x 746 = 22380 = 22380/ 1.73 x 480 x .87 x .87 = 22380/629 = 35.6 amps. The electrical code states that a motor conductor has to be rated at 125% of the motors full load amperage. 35.6 x 125% = 44.5 A #8 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 50 and 55 amps respectively.
There are 746 watts in 1 HP. Watts = amps x volts. It depends on the voltage rating of the motor. Amps = 746/volts = ? need voltage.
Wire is sized by the load amperage. The formula for amperage when the HP is known is I = HP x 746/1.73 x E X %eff x pf. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. I = 60 x 746 = 44760/ 1.73 x 480 x .89 x .89 = 44760/658 = 68 amps. Motor feeders have to be sized to 125% of the motors full load amps. 68 x 125% = 85 amps A #3 copper conductor will limit the voltage drop to3% or less when supplying 85 amps for 220 feet on a 480 volt system.
30 HP at 480 (3 Phase) - 746 multiplied by 30 = 22380 22380 divided by 480 (3 Phase) = 46.5 46.5 divided by 1.73 = 29.5AMPS Motor speed and efficiency may change the actual result. Always refer to the name plate data
To find the amperage of a three phase motor, the following equation needs to be used. Amps = HP x 746/1.73 x Volts x % efficiency x power factor. once all of the values are added you can find the amperage of any Horsepower motor at any three phase voltage. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92.
Depends on the motor and the load on that motor. If the motor is loaded to its capacity, it will draw the same amount of power as it would on 690 volts - which will result in ( 690/480 = ) 144% of normal current, which will thermally damage the motor, or will trip overload protection.
Probably 2-3 HP. <<>> The electrical code book states for estimating values only that a 1.5 HP motor operating on three phase 208 volts draws 6.6 amps. For calculating overload protection and conductor size, the motors nameplate rating should always be used.