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MgCl2=95grams per mole so 105g/95g is 1.10 mols of MgCl2
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∙ 11y ago
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∙ 11y ago105 g
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What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
What is the mass of 1.5 moles of MgCl2?
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl21.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
How many atoms are on one mole of MgCI?
To determine the number of atoms in one mole of MgCl2 (magnesium chloride), you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms/molecules per mole. First, you need to calculate the molar mass of MgCl2. Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol. Chlorine (Cl) has an atomic mass of approximately 35.45 g/mol (rounded to two decimal places). Now, add the atomic masses of one magnesium atom and two chlorine atoms to find the molar mass of MgCl2: MgCl2 molar mass = (1 x Mg atomic mass) + (2 x Cl atomic mass) MgCl2 molar mass = (1 x 24.31 g/mol) + (2 x 35.45 g/mol) MgCl2 molar mass = 24.31 g/mol + 70.90 g/mol MgCl2 molar mass = 95.21 g/mol So, the molar mass of MgCl2 is approximately 95.21 g/mol. Now, using Avogadro's number, you can calculate the number of atoms in one mole of MgCl2: Number of atoms in 1 mole of MgCl2 = 6.022 x 10^23 atoms/molecules per mole Now, divide this by the molar mass of MgCl2 (95.21 g/mol): Number of atoms in 1 mole of MgCl2 = (6.022 x 10^23 atoms/mol) / (95.21 g/mol) Number of atoms in 1 mole of MgCl2 ≈ 6.32 x 10^21 atoms So, there are approximately 6.32 x 10^21 atoms in one mole of MgCl2.
How many moles of magnesium a chloride are produced when a 4.3 grams piece of magnesium is placed in a bottle of hydrochloric acid large enough to completely react with the magnesium?
First of all write down the BALANCED reaction equation. Mg(s) + 2HCl(aq) = MgCl2(aq) + H2(g) We note that the molar ratios are 1:2::1:1 Next calculate the moles of Mg mol(Mg) = 4.3 / 24.3 (Atomic mass) mol(Mg) = 0.17695... Hence by equivalence with the mole ratios 0.17695... moles of MgCl2 are produced. NB 1:2::1:1 becomes 0.17695 , 0.353909...:: 0.17695...:0.17695... 695... : 0.
How many moles of ions are in 27.5 g of MgCl2?
This is a trick question. There are no ions in MgCl2, the ions are bonded together, suspended in a solid. In the case of MgCl2 this is a white power.
124 g of MgCl2 contains __.mol MgCl2?
Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
What is the value of x When a 1.63 g sample of MgCl2xH2O is heated to remove all water a mass of 0.762 g remains?
You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O
100 mL of a 0.1 M MgCl2 solution contains?
use formula mv over 1000 ,so 20 x 0.3 over 1000 you 'll get 0.006 mol.
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
What is the theory yield of magnesium chloride when 5.6 grams of magnesium is reacted with elemental chlorine there is an excess of elemental chlorine the 5.60g magnesium is the limiting reactant?
magnesium + chlorine --> magnesium chloride Mg (s) + Cl2 (g) --> MgCl2 (s) 5.60 g Mg x 1 mol Mg x 1 mol MgCl2 x 95.21 g MgCl2 = 21.9 g MgCl2 ..................24.31 g Mg. 1 mol Mg........ 1 mol MgCl2
How many moles in 53.8 g of magnesium chloride?
Magnesium chloride, MgCl2, has a molecular mass of has a molar mass of 95.21 g/mol. So, 53.8 g MgCl / 95.21 g/mol is 0.565 mol MgCl2.
What is the mass of 1.5 moles of MgCl2?
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl21.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
Are 50 grams of NaCl and 50 grams of MgCl2 the same amount?
No, there will be more molecules in the 50 grams of NaCl, because its molacular weight is lower. NaCl has a molaculair mass of 58.44 g/mol and MgCl2 has a molcular mass of 95.21 g/mol. 50 g / 58.44 g/mol = 0.86 mol NaCl 50 g / 95.21 g/mol = 0.53 mol MgCl2 The avogadro contstant states that 1 mole equals 6.02214179*1023 molecules. So you have 0.86 * 6.022*1023 = 5.18*1023 molecules of NaCl and 0.53 * 6.022*1023 = 3.19*1023 molecules of MgCl2.
How many atoms are on one mole of MgCI?
To determine the number of atoms in one mole of MgCl2 (magnesium chloride), you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms/molecules per mole. First, you need to calculate the molar mass of MgCl2. Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol. Chlorine (Cl) has an atomic mass of approximately 35.45 g/mol (rounded to two decimal places). Now, add the atomic masses of one magnesium atom and two chlorine atoms to find the molar mass of MgCl2: MgCl2 molar mass = (1 x Mg atomic mass) + (2 x Cl atomic mass) MgCl2 molar mass = (1 x 24.31 g/mol) + (2 x 35.45 g/mol) MgCl2 molar mass = 24.31 g/mol + 70.90 g/mol MgCl2 molar mass = 95.21 g/mol So, the molar mass of MgCl2 is approximately 95.21 g/mol. Now, using Avogadro's number, you can calculate the number of atoms in one mole of MgCl2: Number of atoms in 1 mole of MgCl2 = 6.022 x 10^23 atoms/molecules per mole Now, divide this by the molar mass of MgCl2 (95.21 g/mol): Number of atoms in 1 mole of MgCl2 = (6.022 x 10^23 atoms/mol) / (95.21 g/mol) Number of atoms in 1 mole of MgCl2 ≈ 6.32 x 10^21 atoms So, there are approximately 6.32 x 10^21 atoms in one mole of MgCl2.
How many moles of magnesium a chloride are produced when a 4.3 grams piece of magnesium is placed in a bottle of hydrochloric acid large enough to completely react with the magnesium?
First of all write down the BALANCED reaction equation. Mg(s) + 2HCl(aq) = MgCl2(aq) + H2(g) We note that the molar ratios are 1:2::1:1 Next calculate the moles of Mg mol(Mg) = 4.3 / 24.3 (Atomic mass) mol(Mg) = 0.17695... Hence by equivalence with the mole ratios 0.17695... moles of MgCl2 are produced. NB 1:2::1:1 becomes 0.17695 , 0.353909...:: 0.17695...:0.17695... 695... : 0.
How many moles of ions are in 27.5 g of MgCl2?
This is a trick question. There are no ions in MgCl2, the ions are bonded together, suspended in a solid. In the case of MgCl2 this is a white power.
How many formula units make up g of magnesium chloride?
molar mass of MgCl2=95.211g/mol mol=mass/molar mass=34.8g*mol/95.211g=0.3655039859molMgCl2 #of anything=mol*Avogadro's#=0.3655mol*6.022*1023formula units/mol answer= 2.20*1023
