The number of moles is equal to the mass divided by the molar mass. In mathematical form, it is:
Moles = Mass of Mg / Molar Mass of Mg
Moles = 109.4 / 24.3
Moles = 4.501 (rounded to three decimal points)
Always keep a Periodic Table handy, molar masses are quite important.
To determine the number of moles in 109.4g of Mg, divide the given mass by the molar mass of Mg. The molar mass of Mg is approximately 24.305 g/mol. Therefore, 109.4g of Mg will contain approximately 4.5 moles.
To find moles when given grams, divide the Atomic Mass of the element by the weight in grams. The atomic mass of Magnesium is 24.305, so you would divide 24.305 by 109.4, which equals .222166, or .2 when rounded according to significant figures.
About 4.5 moles.
4.50
45 mg contains approximately 1.956 moles of atomic sodium.
1 mole Mg = 6.022 x 1023 atoms Mg 12.04 x 1023 atoms Mg x 1mol Mg/6.022 x 1023 atoms Mg = 1.999 moles Mg
0,0011 moles of hydrogen are obtained.
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
.3
8,23.1023 atoms Mg is equivalent to 1,366 moles.
There are 18.9 moles in 225.8 mg. This is a math problem.
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
The answer is 0,615 moles.
45 mg contains approximately 1.956 moles of atomic sodium.
This is equivalent to 1,4 moles.
The molar mass of oxygen is 32 g.1,2 mg oxygen is equal to 0,0000375 moles.
29,4 mg of BrI is the equivalent of 0,000 143 moles.
14,84 g magnesium are equivalent to 0,61 moles.
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
6,02214129.10ex.23---------------1 mol458.10ex.23---------------------------xx = 76,o5 moles Mg
0.0296 M solution means 1000 ml contains 0.0296 moles of LiI By applying unitary method we get, no. of moles of LiI in 258.6ml =.00765456 moles