Supercalifrigilisticexpialidocious.
A-N-C-I-E-N-T-E-G-Y-P-T {12 Letters}
CAPITAL A B C D E F G H I J K L M N O P Q R S T U V W X Y Z LOWERCASE a b c d e f g h i j k l m n o p q r s t u v w x y z
In the modern English alphabet, consisting of 26 letters, P is the 13th letter.A B C D E F G H I J K L M N O P Q R S T U V W X Y Z = uppercase.a b c d e f g h i j k l m n o p q r s t u v w x y z = lowercase.
A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, AND Z
p > q~qTherefore, ~p| p | q | p > q | ~q | ~p || t | t | t | f | f || t | f | t | t | f || f | t | t | f | t || f | f | t | t | t |
p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
P Q (/P or /Q) T T F T F T F T T F F T
P | T T F F Q | T F T F Q' | F T F T P + Q' | F T F F The layout is the best I could do with this software. Hope it is OK.
it is true when at least one statement is true p q p v q t t t t f t f t t f t f You sure about this?
if weight of the feed, concentrate and tailing are F, C and T respectively and their corresponding assays f, c and t, then: F=C+T Ff=Cc+Tt Ff=Cc+t(F-C) therefore F/C= (c-t)/(f-t) which is the ratio of concentration. the plant recovery equals (Cc/Ff)*100 or based on the ratio of concentration the recovery is: Recovery=100*((f-t)c)/((c-t)f)
31
I have found a tool that can help you h t t p s : // t i k t o k .t r y j e f f r e y . c o m /? r e f = c q 5 ma k p 7 7 w s v 6. thanks
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Supercalifrigilisticexpialidocious.
As we know that the relation between T(F) and T(C) is given by: T(F)=9/5*T(C)+32 Now we want to know the point at which T(F) and T(C) both agrees i.e T(F)=T(C) So the above expression becomes, T(F)=9/5*T(F)+32 By solving above we get -40oC
The four temperature scales are Celsius ( C ) , Fahrenheit ( F ), Kelvin ( K ), and Rankine ( R ).T in C = ( 5/9 ) ( T in F - 32.0 )T in F = ( 9/5 ) ( T in C ) + 32.0T in K = T in C + 273.2T in R = T in F + 459.7