answersLogoWhite

0


Best Answer

0.01 molar

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: 20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

20 ml of acetic acid ch3cooh is titrated with a solution of 0.15 m naoh if 35 ml of naoh are required to reach the equivalence point what is the concentration of the acetic acid solution?

0.26


30 ml of hydrofluoric acid hf is titrated with a solution of 0.10 m koh if 55 ml of koh is required to reach the equivalence point what is the concentration of the acetic acid solution?

0.13 is the concentration of the acetic acid solution.


20ml of acetic acid is titrated with a solutuion of 0.15 m naoh if 35 ml of naoh are required to reach the equivalence point what is the concentration of the acetic acid solution?

.26


50 ml of hcl is titrated with a solution of 0.24 m naoh it requires 35 ml of naoh to reach the equivalence point what is the concentration of the hcl solution?

.17


65 ml of hcl is titrated with a solution of 0.15 m koh it requires 44 ml of koh to reach the equivalence point what is the concentration m of the hcl solution?

0.1


When a formic acid solution is titrated with lithium hydroxide will the solution be acidic neutral or basic at the equivalence point?

basic


How does the equivalence point differ from the half equivalence point?

Equivalence point is reached when Reactants react at Stoichiometric ratios and reach the Endpoint so that no more of the solution being titrated is found.Eg: Strong base + Strong Acid: HCL+NaOH--> NaCl+H2O1mol of Hcl Requires 1 mol of NaCl,Therefore 3.65 moles of Hcl Requires 3.65Moles of NaOH and equivalence point is reached when that much is added to the acid being titrated for example .Half Eq point is when Half of the Solution being titrated has reacted. It is a point on a titration curve which corresponds to the addition of exactly half of the volume of the titrant needed to reach equivalence point (or end point )Corrected:So, at HALF-WAY Eq. point the pH = pKa, since the actual concentration of ACID is equal to concentration of its conjugate BASE because both are equal to HALF of the original (unknown) acid concentration to be titrated (half left = half formed).


A solution containing 3.76 g naoh in 361 ml water is titrated with 491 ml hcl what is the concentration of hcl in the original solution?

The concentration of hcl is 0.13.


A 0.361 molar solution of the weak acid HA with a pKa of 4.039 is titrated with a 0.163 molar solution of NaOH. What is the pH of the solution at the equivalence point of this titration?

You need to know the volume of the weak acid being titrated so you can find how many moles of base are needed to match that of the acid.


65 ml of hci is titrated with a solution of 0.15m koh it requires 44 ml of koh to reach the equivalence point?

MHCl = 0.15*44/65 = 0.10 mol/L


What is a secondary solution?

A solution that has been titrated against a primary standard solution.


A 25 ml sample of 723 m hclo4 is titrated with a 273 m koh solution the h3o concentration after 66.2 ml of koh is?

1.00x10^-7