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Q: 65 ml of hcl is titrated with a solution of 0.15 m koh it requires 44 ml of koh to reach the equivalence point what is the concentration m of the hcl solution?
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50 ml of hcl is titrated with a solution of 0.24 m naoh it requires 35 ml of naoh to reach the equivalence point what is the concentration of the hcl solution?

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How does the equivalence point differ from the half equivalence point?

Equivalence point is reached when Reactants react at Stoichiometric ratios and reach the Endpoint so that no more of the solution being titrated is found.Eg: Strong base + Strong Acid: HCL+NaOH--> NaCl+H2O1mol of Hcl Requires 1 mol of NaCl,Therefore 3.65 moles of Hcl Requires 3.65Moles of NaOH and equivalence point is reached when that much is added to the acid being titrated for example .Half Eq point is when Half of the Solution being titrated has reacted. It is a point on a titration curve which corresponds to the addition of exactly half of the volume of the titrant needed to reach equivalence point (or end point )Corrected:So, at HALF-WAY Eq. point the pH = pKa, since the actual concentration of ACID is equal to concentration of its conjugate BASE because both are equal to HALF of the original (unknown) acid concentration to be titrated (half left = half formed).


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You need to know the volume of the weak acid being titrated so you can find how many moles of base are needed to match that of the acid.


What is a secondary solution?

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A 25 ml sample of 723 m hclo4 is titrated with a 273 m koh solution the h3o concentration after 66.2 ml of koh is?

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