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4volts x 2.8 =9.6 v
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Are peak-to-peak and rms voltage measurements the same?
No, the peak-to-peak voltage is 2sqrt(2) times as much as the rms for a pure sine-wave.
What is the peak voltage of a 240 VRMS sine wave?
To calculate the peak voltage of an RMS voltage in a sine wave simply multiply the RMS voltage with the square root of 2 (aprox. 1,414) like this: 240 x 1,414 = 339,4 V RMS x sqr.root of 2 = peak voltage
If a sine wave has a peak value of 220 volts what is the route means square value?
If the Peak to neutral voltage is 220 volts, the root mean square voltage is 155.6 volts (sqrt(220)).
How does the peak value of an alternating voltage compare to its quoted value?
The quoted value is usually RMS value, i.e it is lesser than the peak value of the voltage, therefore the peak value is sqrt(2) times the quoted value. (it is a sine wave)
Does digital voltmeter measures rms voltage or peak to peak voltage or average?
Yes, most DMM are ''average responding", giving accurate rms reading if the ac voltage signal is a pure sine wave. They measure the average of the absolute value of ac voltage and are calibrated so that reading are corrected to that of the rms value of a sine wave.Error occur if harmonic are present.
Are peak-to-peak and rms voltage measurements the same?
No, the peak-to-peak voltage is 2sqrt(2) times as much as the rms for a pure sine-wave.
What is the approximate peak-to-peak voltage of a 2 VRMS sine wave?
the answer is 5.6vp-p
What is the conversion of rms voltage to Peak to Peak voltage?
Assuming sine wave (it is different if not): Vp-p = 2.828 * Vrms
What is the peak voltage of a 240 VRMS sine wave?
To calculate the peak voltage of an RMS voltage in a sine wave simply multiply the RMS voltage with the square root of 2 (aprox. 1,414) like this: 240 x 1,414 = 339,4 V RMS x sqr.root of 2 = peak voltage
What is the peak voltage of a sine wave that measure 220V AC rms?
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
What is the relationship between peak to peak and peak voltage for a sine wave?
The RMS (root mean square) of the peak voltage of a sine wave is about 0.707 times the peak voltage. Recall that the sine wave represents a changing voltage, and it varies from zero to some positive peak, back to zero, and then down to some negative peak to complete the waveform. The root mean square (RMS) is the so-called "DC equivalent voltage" of the sine wave. The voltage of a sine wave varies as described, while the voltage of a DC source can be held at a constant. The "constant voltage" here, the DC equivalent, is the DC voltage that would have to be applied to a purely resistive load (like the heating element in a toaster, iron or a clothes dryer) to get the same effective heating as the AC voltage (the sine wave). Here's the equation: VoltsRMS = VoltsPeak x 0.707 The 0.707 is half the square root of 2. It's actually about 0.70710678 or so.
What is the instantaneous voltage of a sine wave at 25 degrees if its peak voltage is 30 V?
12.68V 3o * sin25 = 12.67854785
What is the difference of peak and rms value?
RMS stands for "Root of the Means Squared", and is a mathematical method of defining the "operating" voltage of a sine wave power source. Typical home lighting and outlet voltage presently is 120 VAC (volts alternating current), 60 Hz. (Hertz, formerly referred to as "cycles per second".) But the PEAK voltage is the absolute maximum voltage at the "peak" of each sine wave of voltage. Mathematically, the "Peak" voltage is 1.414 (which is the square root of the number 2) times the RMS voltage, and conversely, the RMS voltage is 0.707 times the PEAK voltage.
What is the rms voltage for 144 volts modified sine wave?
if that 144 is the peak voltage if its a sine wave the rms voltage is that voltage divided by sqrt(2) if not a sine wave (modified) you must find the area under the curve by integrating a cycle of that wave shape (root mean squared)
What is the peak-to peak voltage of a 56 Vrms ac voltage?
For a sine wave, the form factor is the square root of 2. Thus, the effective voltage of 56 V (56 Vrms) is 2-1/2 times the peak-to-peak voltage. Thus, the peak-to-peak voltage Vpp = Vrms * sqrt(2)In this example:Vpp = 56V * 1.4142... = 79.2V (rounded to one decimal place)
What is the rms of 10v?
The rms of 10V is 6.02V. Take the peak voltage of the sine wave and multiply it by 0.707.
If a sine wave has a peak value of 220 volts what is the route means square value?
If the Peak to neutral voltage is 220 volts, the root mean square voltage is 155.6 volts (sqrt(220)).
