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When body have 2ms accleration in 15 seconds with a velocity 30ms does the velocity of the car uniform?
Although the question is stated in a somewhat confusing way, we can state withconfidence that the velocity of the car is NOT uniform, because a value is given forits acceleration. 'Uniform' motion means zero acceleration.
Calculate a car goes from 20ms to 30ms in 10 seconds. what is its acceleration?
The car's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: (30 m/s - 20 m/s) / 10 sec = 1 m/s^2. The car's acceleration is 1 meter per second squared.
What is a story problem for acceleration?
Jack is driving a car. As he passes post 1 he is travelling at 15ms-1 and starts to accelerate at a steady speed. 8 seconds later he passes post 2 travelling at 30ms-1. Post 1 and 2 are What is his acceleration during this time?
A car accelerates from rest and accelerates at 3 ms-2 how long it will take to reach a velocity of 30ms-1?
Acceleration = (change in speed) / (time for the change)3 = (30) / (time)3 x (time) = 30time = 30/3 = 10 seconds
A body of mass 2kg is moving with a uniform speed of 30ms-¹ a force of 6N is appiled against the direction of motionhow much distance with the body move in 5second after that?
The force applied will decelerate the body. The acceleration can be calculated using the equation F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, the acceleration will be -3 m/s^2 (negative because it's in the opposite direction to the velocity). Using the equation v = u+at, where v is final velocity, u is initial velocity, a is acceleration, and t is time, you can find the final velocity after 5 seconds. Finally, use the equation s = ut + 0.5at^2 to find the distance moved after 5 seconds.
A 500kg truck moving a 30ms strikes a parked car and they connect together and move forward what is the speed of the car and truck as they move forward connected together?
Momentum = mass x velocity. You already stated the mass and velocity so you can figure out the momentum.
If an car has a mass of 400 kg and a velocity of 30ms to the east what is the magnitude of its momentum?
The momentum of the car is given by the formula: momentum = mass x velocity. Plugging in the values, the momentum of the car is 400 kg x 30 m/s = 12000 kg*m/s.
Two buses depart from Chicago and going to New York and one to San Francisco. Each bus travels at a speed of 30ms. Do these buses have equal velocities explain.?
No the two buses do not have equal velocities because VELOCITY is the SPEED in a given DIRECTION. One would have a velocity of +30m/s because it is traveling in one direction, and the other would have a velocity of -30m/s because it is traveling in the opposite direction.
If a projectile is fired straight up in the air at a speed of 30ms the total time to return to its starting point is about?
Assuming no air resistance, the time it takes for the projectile to return to its starting point is twice the time it takes to reach the highest point of its trajectory. The time to reach the highest point can be calculated using the equation: time = initial velocity / acceleration due to gravity. Therefore, the total time for the projectile to return would be around 6 seconds.
A car is travelling at 30ms driver sees a danger ahead sign and does an emergency stop reaction time is 0.6s calculate how far the car travels before the driver starts to press the brake pedal?
Your answer is 18 meters 30 * 0.6 = 18
A ball is shot out of a cannon with initial velocity 30ms at 30 degree above the horizontal. How long is ball in the air How far away from the cannon does the ball hit What the max height by ball?
The time the ball is in the air can be found using the vertical motion equation: time = 2 * (initial vertical velocity) / (gravity). The range can be calculated using the horizontal motion equation: range = (initial velocity)^2 * sin(2*launch angle) / gravity. The maximum height can be determined by finding the vertical component of the flight time and substituting that into the vertical motion equation: max height = (initial vertical velocity)^2 / (2 * gravity).
A car is moving at a constant speed of 30ms the combined mass of the car and the driver is 1000kg if the driving force is 3000N what is the value of the frictional force?
If the car and driver are moving (along a flat horizontal surface) at constant speed, then there is no acceleration, and the net horizontal force is zero.The applied 3,000N must be canceled by an effective total 3,000N of friction.
