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Although the question is stated in a somewhat confusing way, we can state withconfidence that the velocity of the car is NOT uniform, because a value is given forits acceleration. 'Uniform' motion means zero acceleration.
The car's acceleration can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Plugging in the values, we get: (30 m/s - 20 m/s) / 10 sec = 1 m/s^2. The car's acceleration is 1 meter per second squared.
Jack is driving a car. As he passes post 1 he is travelling at 15ms-1 and starts to accelerate at a steady speed. 8 seconds later he passes post 2 travelling at 30ms-1. Post 1 and 2 are What is his acceleration during this time?
Acceleration = (change in speed) / (time for the change)3 = (30) / (time)3 x (time) = 30time = 30/3 = 10 seconds
The force applied will decelerate the body. The acceleration can be calculated using the equation F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, the acceleration will be -3 m/s^2 (negative because it's in the opposite direction to the velocity). Using the equation v = u+at, where v is final velocity, u is initial velocity, a is acceleration, and t is time, you can find the final velocity after 5 seconds. Finally, use the equation s = ut + 0.5at^2 to find the distance moved after 5 seconds.
Momentum = mass x velocity. You already stated the mass and velocity so you can figure out the momentum.
The momentum of the car is given by the formula: momentum = mass x velocity. Plugging in the values, the momentum of the car is 400 kg x 30 m/s = 12000 kg*m/s.
No the two buses do not have equal velocities because VELOCITY is the SPEED in a given DIRECTION. One would have a velocity of +30m/s because it is traveling in one direction, and the other would have a velocity of -30m/s because it is traveling in the opposite direction.
Assuming no air resistance, the time it takes for the projectile to return to its starting point is twice the time it takes to reach the highest point of its trajectory. The time to reach the highest point can be calculated using the equation: time = initial velocity / acceleration due to gravity. Therefore, the total time for the projectile to return would be around 6 seconds.
Your answer is 18 meters 30 * 0.6 = 18
The time the ball is in the air can be found using the vertical motion equation: time = 2 * (initial vertical velocity) / (gravity). The range can be calculated using the horizontal motion equation: range = (initial velocity)^2 * sin(2*launch angle) / gravity. The maximum height can be determined by finding the vertical component of the flight time and substituting that into the vertical motion equation: max height = (initial vertical velocity)^2 / (2 * gravity).
If the car and driver are moving (along a flat horizontal surface) at constant speed, then there is no acceleration, and the net horizontal force is zero.The applied 3,000N must be canceled by an effective total 3,000N of friction.