For calculation purposes R = E/I. R = 120/15. R = 8 ohms. This is hypothetical because of the internal components that make up most appliances.
voltage = currentresistance [v=IR] so R=V/ I so Resistance=120/15=8 Amps
The equation that you are looking for is R = Volts/Amps.
If it is a 32-amp circuit you can use any appliance that takes less than 32 amps. That includes a 15-amp appliance. All appliances fed from that circuit must use 32 amps or less in total.
Current or AMPS are what the appliance draws or load of the appliance. So, if you have a say 10,000 amps going thru a cable rated for say 1,000 amps , guess what ,the cable over heats and either will melt or at least catch fire.
The resistance of the circuit will be 46 ohms
AWG 10.
Volts = Amps x Resistance Therefore Amps = Volts / Resistance
12 volts.
Let R be the resistance, V the voltage, and I the current R = V / I R = 120 / 24 R = 5 ohm
The formula is Resistance= Voltage/ Amps(current) In your example: R=50/2.5, so the answer is 20 ohms.
Excessive resistance (drag), will cause motor to draw more amps (current flow) to operate.
In the U.S. 120 volts. <<>> Using the equation E = I x R, Volts = Amps x Resistance = 110 volts.
No.
You use Ohm's Law to make your calculation. Volts = Amps x Resistance Amps = Volts / Resistance
It requires the ability to multiply and divide. It requires the ability to mentally separate voltage from current and to understand resistance and when to add resistance for series circuits and worse identify and calculate parallel loads.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
Nothing drastic happens, the appliance will operate as normal. The voltages 220 to 240 volts are a nominal figure in the same voltage range. It is brought about by the power company, as they have a responsibility to keep voltages within a certain 10% range. The load will only notice a difference of 1% on the load current. e.g. Wattage load of 2400. Amps = watts/volts. 2400/230V = 10.4 amps. 2400/220V = 10.9 amps. On a constant resistance as the voltage goes lower, the current goes higher and vise versa as the voltage goes higher, the current goes lower.
Amps (current) times volts = watts. so watts divided by volts = current (Amps). i.e.- 0.5 Amps.
The equation that you are looking for is I = E/R. Amps = Volts/Resistance.