A 4000-Ω resistor is connected across 220 V will have a current flow of 0.055 A.
Ohm's law: Voltage equals Current times Resistance
Four 1000 ohm resistors in series have an effective resistance of 4000 ohms. Across a 4 volt voltage source, they would have a current of 1 mA, with a power dissipation of 4mW.
CT ratio is the ratio of primary (input) current to secondary (output) current. A CT with a listed ratio of 4000:1 would provide 1A of output current, when the primary current was 4000A.
Start with 2000 of P then add 1000 of S an at the end add 1000 of I mix it very good .After about 45 days you will have 4000 p,s and I which stand for 4000 PSI
700 pounds
4000 years old.
Four 1000 ohm resistors in series have an effective resistance of 4000 ohms. Across a 4 volt voltage source, they would have a current of 1 mA, with a power dissipation of 4mW.
Using ohm's law, V=IR then R=V/I =6/0.0015=4000 ohm = 4k ohm resistor.
use ohm s law ( v =rxi ) ( i =v/r) ( r=v/i) therefore your answer is 10v/4000=.0025amps
The selection of CT Sizing is based on total connected load. If for example a Main CB of 2000 KVA Trafo is 4000 A -- then best selection would be 4000:5 -- this would match also in the Energy Meter (KWH Meter) with 800 as multiplier.
The distance across Australia, travelling east-west is approximately 4000 kilometers
Bunny OS 4000 is a series of operating systems made by Horatiu. There is Bunny OS 4000 SP1 Bunny OS 4000 SP2 Bunny OS 4000 SP3 Bunny OS 4000 SP4 And current Beta testing of Bunny OS SP5.
CT ratio is the ratio of primary (input) current to secondary (output) current. A CT with a listed ratio of 4000:1 would provide 1A of output current, when the primary current was 4000A.
There are hundreds of them across the globe.
Brian Walsh and Esdras Accime are tied for it
Pay scale 10050 & Grade Pay 2400
4000% of 4000 =4000/100 * 4000 =160,000
To analyze the given electrical circuit, we'll use Kirchhoff's voltage law (KVL) and the relationship between voltage, current, resistance, and inductance. Kirchhoff's voltage law states that the sum of the voltage drops across the components in a closed loop is equal to the electromotive force (EMF) in that loop. Let's break down the given circuit: Electromotive Force (EMF): The EMF is given by E(t) = 100 sin(40t) V, where t represents time in seconds. Resistor: The resistor has a resistance of 10 Ω. Inductor: The inductor has an inductance of 0.5 H. Current: The current flowing through the circuit is denoted as i(t) and is initially 0 A. To find the current i(t) in the circuit, we'll apply KVL. The sum of the voltage drops across the resistor and the inductor should be equal to the EMF. Voltage drop across the resistor: V_R = i(t) * R = 10i(t) Ω Voltage drop across the inductor: V_L = L * di(t)/dt = 0.5(di(t)/dt) H Applying KVL: E(t) = V_R + V_L 100 sin(40t) = 10i(t) + 0.5(di(t)/dt) To solve this second-order linear differential equation, we need to differentiate the equation with respect to time (t): d/dt (100 sin(40t)) = d/dt (10i(t) + 0.5(di(t)/dt)) 4000 cos(40t) = 10(di(t)/dt) + 0.5(d^2i(t)/dt^2) Now we have a second-order differential equation in terms of i(t). Rearranging the terms: 0.5(d^2i(t)/dt^2) + 10(di(t)/dt) - 4000 cos(40t) = 0 To solve this differential equation, we need to find the particular solution for i(t) that satisfies the initial condition i(0) = 0. The general solution will involve complementary and particular solutions. Unfortunately, the given differential equation is nonlinear, and there is no simple analytical solution. To obtain the complete details of the current waveform, we'll need to solve this differential equation numerically using techniques like numerical integration or simulation software such as SPICE