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12.5. MA=Output Force/Input Force, so MA=5000N/400N=12.5 Note that there isn't a unit because N/N cancels out.
The question does not have enough information for a single answer. All we can tell from the question as is is that the friciton force must be less than 5000N. To give a definite number to the magnitude of the friction force we need to know at what rate the wagon is accelerating when the pull is 5000N.
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It takes 8 pounds of pressure per square inch to break somebody's jaw.
Ans. :- net acceleration = 40000 - 5000 = 35000 N.
Friction is one of the many various types of retardant forces that resist motion. To the point, friction reduces the net force in a direction by acting in the opposite direction (effectively slowing it down). Take for example a car driving along the road. The car could be generating a force of say 5000 Newtons to the right and as a result of the tyres contacting the road surface, a frictional force of say 500N is generated to the left. This means that the net force is 4500N to the right. Take note then for this example if the frictional force was 5000N the car would be stationary.
where, F = force, a = acceleration, vi = velocity initial, xf = position final, xi = position initial.F = ma5000 = 1500(a)a = 5000/1500 = 3.33 m/s^2v^2 = vi^2 +2a[xf - xi]assuming it started from rest, we havev = [0+2(3.33)(100-0)]^.5v = 25.8 m/s
On Earth, 65 kg of mass weighs 637.5 newtons (143.3 pounds). (both rounded)
well im looking for that answer but havent quite found it but i got this.....The truss elements are subjected only to tensile and compressive loads, and thus are designed accordingly. Truss bridges are not intended to withstand the bending forces, and are best suitable for the straight alignments. A truss bridge is designed to endure extreme weights and also cover extended gaps.