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A box of mass 2 kg is set down on a plane inclined 30 degrees from the horizontal The coefficient of static friction is .5 the coefficient of kinetic friction is 0 What is the speed after 3 second?
Wiki User
∙ 14y ago
the maximum value of limiting friction is = coff. of static fric. * normal force.
in this case normal force =mgcosA=17N.
the coff=0.5 so the maximum friction=0.5*17=8.5N.
but the force acting downward on the incline is mgsinA which is =2*10*0.5=10N.
as it has breached the value of friction,the block will move.now kinetic fric. will act.As the coff. of kinetic fric.=0,the surface is as good as a frictionless one.use the laws of kinematics to find the velocity(v=u+at,a=gsinA,t=3,u=0)
hence the answer is=15m/s.
in reality if there is a coff of static fric,ther ewill be a coff.of kinetic fric.
good luck.
regards
carlitos tevez.
Wiki User
∙ 14y ago
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A block accelerates at 3.2 down a plane inclined at an angle 30 degrees. Acceleration of gravity is 9.8. Whats the coefficient of static friction between the block and the inclined plane?
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A block accelerates at 3.2 down a plane inclined at an angle 30 degrees. Acceleration of gravity is 9.8. Whats the coefficient of static friction between the block and the inclined plane?
Static friction does not apply when the block is already moving. Without friction, the force on the block parallel to the surface of the incline is Fg*sin(angle), so the acceleration without friction is 9.8* sin(30) = 9.8 * (1/2) = 4.9 Since it is accelerating at 3.2, friction is slowing down the block by (4.9-3.2 = 1.7). The coefficient of kinetic friction is (1.7/4.9) = 0.346939
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How do you find the minimum coefficient of static friction for a mass on an incline of 32 degrees?
The equation for friction is F=uN. F (friction), u (coefficient of friction), and N (normal). So you first need to solve for the normal by using Newton's second law. Also solve for the x component of the gravity force. Since it is static friction, you know it should be at rest, so that x component force should be the same as the force of friction. Knowing that and the normal, plug it into the equation and solve for u.
