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A boy kicks a football with an initial velocity of 28.0 ms at an angle of 60.0 above the horizontal What is the highest elevation reached by the football in its trajectory?
Wiki User
∙ 16y ago
Use the equation Vy=Voy-gt
Because we are talking about the highest point we know that Vy=0 (i.e. the football is no longer moving up). Therefore set the equation equal to zero
0=Voy-gt
Voy=gt
Next, use the equation Voy=sin(theta)
Replace Voy with "gt" because Voy=gt in this case (see above)
You get: gt=sin(theta)
You know theta = 20 degrees and t=2seconds
G is a constant that = 9.81m/s^2
Plug in the numbers
Christie
Wiki User
∙ 8y ago
Wiki User
∙ 16y ago30m
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