Use the equation Vy=Voy-gt
Because we are talking about the highest point we know that Vy=0 (i.e. the football is no longer moving up). Therefore set the equation equal to zero
0=Voy-gt
Voy=gt
Next, use the equation Voy=sin(theta)
Replace Voy with "gt" because Voy=gt in this case (see above)
You get: gt=sin(theta)
You know theta = 20 degrees and t=2seconds
G is a constant that = 9.81m/s^2
Plug in the numbers
Christie
At the top of its trajectory, a projectile's vertical velocity is momentarily zero, while its horizontal velocity remains constant. The speed of a projectile at the top of its trajectory can be determined by calculating the magnitude of its velocity vector using the horizontal and vertical components of velocity.
At the highest point of its trajectory, the direction of an oblique projectile will be horizontal. This means that the projectile will momentarily have zero vertical velocity and only horizontal velocity.
The initial velocity of the football can be easily found by solving for the magnitude of the vector formed by adding the two components given. This is accomplished using the Pythagorean theorem. The initial velocity of the football is approximately 26.2 m/s.
The horizontal velocity of a projectile remains constant if there is no air resistance or external forces acting horizontally. This means that the horizontal component of the projectile's velocity does not change throughout its trajectory, only its vertical component is affected by gravity.
Assuming that there is no velocity in the horizontal direction, then the velocity at that instant is zero.
At the top of its trajectory, a projectile's vertical velocity is momentarily zero, while its horizontal velocity remains constant. The speed of a projectile at the top of its trajectory can be determined by calculating the magnitude of its velocity vector using the horizontal and vertical components of velocity.
At the highest point of its trajectory, the direction of an oblique projectile will be horizontal. This means that the projectile will momentarily have zero vertical velocity and only horizontal velocity.
The initial velocity of the football can be easily found by solving for the magnitude of the vector formed by adding the two components given. This is accomplished using the Pythagorean theorem. The initial velocity of the football is approximately 26.2 m/s.
The horizontal velocity of a projectile remains constant if there is no air resistance or external forces acting horizontally. This means that the horizontal component of the projectile's velocity does not change throughout its trajectory, only its vertical component is affected by gravity.
Assuming that there is no velocity in the horizontal direction, then the velocity at that instant is zero.
The curved path is called a parabolic trajectory. This occurs due to the combination of the projectile's initial horizontal velocity and the acceleration due to gravity in the vertical direction.
Depending on the shape, speed and change in attitude (especially a tendency to tumble) of the projectile its losses of speed at various instants along its trajectory could be quite considerable owing to friction. Under many conditions air friction is proportional to the fourth power of speed. Thus, the horizontal component of the trajectory could be subject to considerable loss of magnitude. As one would expect the shape of the projectile will affect it's path considerably too.
Yes, in the absence of air resistance, a projectile launched into space at any angle will have a constant horizontal velocity. This is because there are no horizontal forces acting on the projectile once it is launched.
Increasing the initial horizontal velocity of an object would cause it to cover more horizontal distance in the same amount of time, leading to a longer horizontal range. The object would maintain the same vertical acceleration due to gravity, so it would still follow a parabolic trajectory but reach a farther horizontal distance before hitting the ground.
Lateral displacement, or the horizontal distance a projectile travels from its initial path, does not affect the trajectory of a projectile in terms of its vertical motion. The vertical motion of a projectile is determined by gravity and initial velocity, while the horizontal motion is affected by factors such as wind resistance and launch angle. Therefore, lateral displacement does not change the overall trajectory of a projectile.
In projectile motion, the horizontal acceleration (ax) is equal to 0 because there are no external horizontal forces acting on the object once it is launched. This means that the object continues to move at a constant horizontal velocity throughout its trajectory.
Objects thrown in the air follow a parabolic path due to the combination of their initial horizontal velocity and the force of gravity acting on them. Gravity pulls the object downward while the initial velocity creates a horizontal motion, resulting in the arched trajectory.