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HC9H7O4+KOH--> [C9H7O4]-K+ +H2O

moles of KOH= 0.300mol/L x 0.0294L

=8.82x10^-4 mol KOH

1 mole of KOH=1 mole of HC9H7O4

moles of HC9H7O4= 8.82x10^-4 mol

mass of aspirin= 8.82x10^-4 mol x 180.09 g/mol

= 0.15884 g

250mg=0.25g

%weight= (weight of solute/weight of sample) x 100%

= ( 0.15884g/0.25g) x 100%

=63.54% of aspirin

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Q: A certain pain reliever was analyzed for aspirin by dissolving 250 mg of the tablet in water and titrating with .0300M KOH Titration required 29.40 mL of base What is percentage by weight of aspirin?
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