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Ohms law states

Voltage = Current X Resistance, or as commonly represented, E=IR.

In this case plugging in the values (using basic algebra)

20 = 2R

or

10 = R

or as commonly stated

R=10.

So that lets us know the TOTAL resistance of the circuit.

Now, knowing that series resistance is "added", we can calculate the individual circuit resistance.

In a series circuit total resistance can be represented by 'R', and the individual resistance of each resistor can be represented by "R1", "R2", R3", and so forth. In a series circuit resistances can be calculated using the formula: R=R1+R2+R3...

Since we only have the two resistors the formula would be:

R=R1+R2

Knowing that the resistors are equal in value we can assume:

R=R1+R1

OR

R=2(R1)

OR

2(R1) = R

OR

R1 = 1/2R

Given that R is 10 (from above)

R1=1/2 * 10

or

R1 = 5

Each resistor equals 5 ohms

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Q: A circuit has two resistors of equal value in series The voltage and current in the circuit are 20 volts and 2 amps respectively What is the value of EACH resistor?
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