5500Watts/220V=25 Amps
It is not necessary, there is no power consumption when the dryer is not in operation.
An electric clothes dryer demands 22A from a 240V outlet at approximately 90% Power Factor. The power demand on the outlet should be about 240V x 22A x 0.9 = 4.75 kW. The active components in an electric clothes dryer are the heating element (100% PF) and the electric motor that turns the tumbler (70-80% PF). The formula you are looking for is W = I x E. (W is watts, I is current in amps, E is volts)
You can generalize that any device that produces heatuses a larger electric current (and more electric power).Some examples are: Toaster, hair dryer, hair curler, clothes iron.The iron operates on more current, and uses more power, than the shaver.
No, the battery connected to an inverter would not have near enough power to run a dryer.
It is a the current drawn by the application that is connected to the power source
4800 watts because watts = volts x amps.
its a kind of electric machine it works by electric power
As far as I know, you can't. It would be safer to have a new outlet installed closer to the dryer.
A 'live' or 'hot' wire is a wire that is connected to a power source. This wire supplies voltage to a load ( light bulb, hair dryer, etc.). When the load is also connected a neutral or another live wire this becomes a path for the flow of current (amps) known as a circuit.
No. -They are different amperages and different plugs. You can NOT swap them.
Current.
watts = volts X amps, so: 15A X 240V = 3600 watts