The pressure will be the sum of pressures of oil and water:
p = rowater g hwater + rooil g hoil
Specific gravity of 0.8 of oil means it's 0.8 times as dense as water:
rooil = 0.8 rowater
Pressure will be then:
p = g (rowater hwater + 0.8 rowater hoil), or numerically:
p = 4355.64 Pa
Head pressure=specific gravity*1000*gravity*height. Therefore if specific gravity is increased head pressure will increase.
There is no such thing as a specific gravity for any element.
If its in a container, pressure is downward and outward due to gravity and confinement respectively. If its on a flat surface without confinement, the pressure is exerted downwards on the surface and the boundaries are held by a combination of adhesion and cohesion.
This question does not provide enough information on the relevant parameters to even attempt an answer. One would assume that if the hole is at the bottom of the container (and not on the side at the bottom) and the liquid is coming out of the hole only due to gravity that the the container would remain stationary. If there is internal pressure in the container, then the initial pressure becomes important as does the time since the water began to flow. If the hole is on the side of the container, then friction between the container and the surface it is resting on become significant. If the container is not circular in cross section, then the location of the hole along the side helps determine whether the container moves laterally or spins.
Oil has the highest specific gravity. Water has the second.
Head pressure=specific gravity*1000*gravity*height. Therefore if specific gravity is increased head pressure will increase.
but i think the absolute pressure is P(pressure)/{p(density)*g(gravity)}
87
The specific gravity is the ratio between the density of a material and the density of water, at a given temperature and pressure.
Specific gravity, (similar to density) has no meaning for a gas, since the density varies with pressure and temperature.
No, the absolute pressure in a liquid of constant density would not double in this situation. This is because the atmospheric pressure is an independent variable, so it will keep the absolute pressure from doubling.
Density, Viscosjty, pressure, specific weight, specific gravity, specific volume
This is called the Specific Gravity of a substance. The density of the material divided by the density of water yields the specific gravity, a specific gravity greater than 1 indicates the substance will sink in water. A specific gravity less than 1 indicates the substance will float in water. Because the units expressed in density cancel each other out specific gravity has no unit dimensions. example: substance 1 has a density of 12 grams per ml water has a density of 1 g/ml then substance 1 has a specific gravity of 12. 12 g/ml / 1 g/ml = 12 *note: for true specific gravity the atmospheric pressure, absolute , and the temperature absolute of both the sample material and the water must be indicated in the calculations as well. ** for gasses the constant or reference medium is air
This ratio is called the specific gravity.
- The specific weight is the weight of a known volume of material at a given temperature and pressure; the unit of measure is kN/m3. - But if you think to relative density: Relative density (specific gravity) is the ratio between the density of the material to be tested and the density of water, at a given temperature and pressure; consequently no unit of measure for this ratio.
The gas's pressure is defined as the outward push against the walls of its container, though gravity contributes to this somewhat. More importantly, this pressure can cause the gases to condense into liquids if it's high enough.
Is this a school question that you simply don't know the answer to?