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No, the absolute pressure in a liquid of constant density would not double in this situation. This is because the atmospheric pressure is an independent variable, so it will keep the absolute pressure from doubling.

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No, it does not. (absolute pressure) = (Pressure Gauge) - (Atmospheric pressure) ==>

(Pabs) = (density of liquid)(gravity)(depth or height) - (Patm)

As you can see, atmospheric pressure is independent of the height/depth. The atmospheric pressure will not double, restricting absolute pressure from doubling.

However, the Gauge Pressure will double.

Q: Does absolute pressure in a liquid of constant density double when the depth is doubled?

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The volume doubles

Since Pressure=Force/Area, if the area is doubled then pressure will be halved.For example, with a force of 10 N and two areas: Pressure = 10/5 = 2 Pa for an area of 5 metes squaredPressure = 10/10 = 1 Pa for an area of 10 meters squaredPressure is halved when area is doubled while the force is constant. This works in a similar fashion for other areas, such as if area is tripled then pressure is 1/3 of the original, or if area is ten times bigger then the pressure will be 1/10 of the original value. If the area is halved then the pressure is doubled and so on.The presser is inversely proportional to the area on condition that the force is the same.

When the force is doubled the pressure is doubled as well. Read Newton's law.

If speed/velocity is doubled and mass remains constant, then kinetic energy becomes quadrupled.

Doubled.

Related questions

if kelvin temp is halved, the volume is halved if pressure is constant.

Since P = F/A, PA = F So, if area is doubled, pressure is halved.

when the contact area is doubled keeping the force constant on the boy, there will be less impact on the body .

If the volume of a container of air is reduced by one half the partial pressure of the oxygen with in the container will be doubled. If the volume of a container of gas is reduced, the pressure inside the container will increase.

.. thenEITHER the pressure is halved for the same amount (moles) of gas,ORthe amount (moles) of gas is doubled at the same pressure,ORany valid combination of these possibillities.

At a constant volume the pressure increase.

Pressure will be doubled as well, if done in the samevolume (so: not in a balloon I mean).(Gas law: p/T=constant )

If the volume is halved, without change in mass, the density will be doubled.

The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1

pV = nRT we can firstly assume that n (number of moles) and R (gas constant) do not change and as pressure is also kept constant, the temperature must be proportional to the volume. Thus if temperature is increased from 27C (300K) to 327C (600K) and is doubled, the volume must also double.

When volume is increased two times, mass is also doubled. This is because density of a particular material always remains constant, (d=m/v), so to keep density constant, volume increase is balanced by mass increase.

The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.