a) Current = (.5/3) = .166A (166mA).
b) Effective resistance = (3/.166) = 18.07 ohms.
The output of a flashlight is its light
P=v*i i=p/v=0.5/3=1/6 (a)
A flashlight outputs light and heat.
A flashlight outputs light and heat.
Output voltage (...of a transformer, for example...) will decrease as it is loaded because of the transformer's internal resistance. As output current increases/load resistance decreases, a larger voltage will be dropped across the internal transformer resistance. This same phenomenon is present in AC and DC systems (such as batteries).
A beam of light.
A beam of light.
The bulb is the output. It is what illuminates the dark.
A series regulator maintains the output voltage at a constant level by constantly changing the effective resistance of the pass device, usually the output transistor.
A beam of light.
output resistance decreases and input resistance increases
depends on the voltage of the batteries.. four 12 volt car batteries would output 4x12 = 48 v