when asking this question they are looking for the number of Br2 therefore .5 mol
.5*6.022*1023 molecules which equals 3.011*1023 molecules
A flask contains 0.410 of liquid bromine, . Determine the number of bromine molecules present in the flask.
A flask contains 0.120mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask
2,288.1023 molecules
.290 x (6.022 x 10^23) = 1.75 x 10^23
The value 6.022 x 10^23 is called Avogadro's number. So you multiply the amount by this number to determine the molecules..270 X (6.022x10^23) = 1.63 x 10^23
A flask contains 0.410 of liquid bromine, . Determine the number of bromine molecules present in the flask.
A flask contains 0.120mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask
2,288.1023 molecules
.290 x (6.022 x 10^23) = 1.75 x 10^23
The value 6.022 x 10^23 is called Avogadro's number. So you multiply the amount by this number to determine the molecules..270 X (6.022x10^23) = 1.63 x 10^23
.310 MOLES 6.022*(10^23 ) molecules --------------- times ------------------------------------ = 1.8668 * 10^23 molecules 1 mole because there are 3 sig figs the answer should reflect that number. so the answer is 1.87 * 10^23 molecules
904,000,000,000,000,000,000,000 (9.04 X 10^23) Bromine atoms.
Hydrogen and Bromine. Similar to hydrogen chloride it dissolves in water to form hydrobromic acid.
Your question is irrelevant. I think that you were trying to find the number of molecules present in half a mole of water. 1 mole of water contains 6.023 * 1023 number of molecules. Hence half mole contains half of that number of molecules which is 3.0115*1023.
Stratosphere contains the ozone layer. It is present as a pool of ozone molecules.
depends on what salt it is and the purity of the water. if the water is 100% pure , then it contains only hydrogen and oxygen as molecules and if it is common salt then it contains sodium and chlorine as molecules
if you have a water sample that contains either nitrate chloride.