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.. thenEITHER the pressure is halved for the same amount (moles) of gas,ORthe amount (moles) of gas is doubled at the same pressure,ORany valid combination of these possibillities.
If the volume of a container of air is reduced by one half the partial pressure of the oxygen with in the container will be doubled. If the volume of a container of gas is reduced, the pressure inside the container will increase.
Charles Law (also known as the law of volumes) describes how gases tend to expand or contract with temperature changes.If the temperature changes and the gas molecules and pressure remains the same then the volume will increase or decrease at the same rate that the temperature changes.Since the temperature doubled the volume will double to 6L.
The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1
Gases Boyle's law states that the Volume of a given amount of gas at constant Temperature varies inversely proportional to Pressure. You have a given volume of gas, and you double its pressure keeping Temperature constant, the volume will reduce by half.
if kelvin temp is halved, the volume is halved if pressure is constant.
.. thenEITHER the pressure is halved for the same amount (moles) of gas,ORthe amount (moles) of gas is doubled at the same pressure,ORany valid combination of these possibillities.
If the volume of a container of air is reduced by one half the partial pressure of the oxygen with in the container will be doubled. If the volume of a container of gas is reduced, the pressure inside the container will increase.
Charles Law (also known as the law of volumes) describes how gases tend to expand or contract with temperature changes.If the temperature changes and the gas molecules and pressure remains the same then the volume will increase or decrease at the same rate that the temperature changes.Since the temperature doubled the volume will double to 6L.
The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1
Because kelvin temperature has a simple relationship with volume, according to Charles's' law if the kelvin temperature becomes doubled at constant pressure the volume of the gas also becomes doubled, this relation is not with Celsius or Fahrenheit temperature.
pV = nRT we can firstly assume that n (number of moles) and R (gas constant) do not change and as pressure is also kept constant, the temperature must be proportional to the volume. Thus if temperature is increased from 27C (300K) to 327C (600K) and is doubled, the volume must also double.
Pressure will be doubled as well, if done in the samevolume (so: not in a balloon I mean).(Gas law: p/T=constant )
half
Gases Boyle's law states that the Volume of a given amount of gas at constant Temperature varies inversely proportional to Pressure. You have a given volume of gas, and you double its pressure keeping Temperature constant, the volume will reduce by half.
Since P = F/A, PA = F So, if area is doubled, pressure is halved.
when the contact area is doubled keeping the force constant on the boy, there will be less impact on the body .