He would have the recessive phenotype for that trait.
recessive
In Pea tallness is dominant but in man it is recessive .
The phenotypic ratio of the offspring when a tall man marries a short woman is 3:1 (tall/short). The phenotypic ratio is figured by using the punnet square with the dominant allele for tall and the recessive allele for the short gene.
50%
50%AnswerColourblindness is a sex-linked recessive mutation i.e. the mutation is carried on the X chromosome. If a colour blind man married a carrier woman they could produce a carrier daughter, a colour blind daughter, a normal son or a colour blind son. The probability of each phenotype occurring is 25%.If XC represents the normal allele for seeing colour and Xc represents the colour blind allele the genotypes of the possible offspring would be as follows:Carrier daughter = XCXcColour blind daughter = XcXcNormal son = XCYColour blind son = XcYThis information is incorrect. In fact a woman can be color blind. My mother is color blind as are my brothers. My sister and I are not though we carry the gene. I have two daughters and one is color blind and the other is not color blind.The information I gave is not incorrect - I have included the possibility of that 'mating' producing a colour blind female child.
As long as you aren't talking about a trait or gene that behaves co-dominately or some other exception, the man would have the dominant trait show up and his alleles would be dominant and recessive (or Dd if you are using letter symbols for the alleles- upper case being the dominant allele from the mom's egg and lower case for the recessive allele from the dad's sperm). So for example if we are talking about the gene for earlobes we can use the letter E to represent the two alleles or genetic variations: E for un-attached earlobes and e for attached earlobes. A sex cell (sperm or egg) has one allele each so that when they unite to make an embryo the new person has 2 alleles- one from each parent. So if the man inherited a dominant allele E from his mom and a recessive allele e from his father then he would have Ee as his "genotype"(what alleles he has). His "phenotype" is what trait he shows, which would be what ever is dominant-- in this case E equals un-attached earlobes.
DNAactually it is not DNA at all, a dominant trait, masks a recessive trait.
recessive
In Pea tallness is dominant but in man it is recessive .
The phenotypic ratio of the offspring when a tall man marries a short woman is 3:1 (tall/short). The phenotypic ratio is figured by using the punnet square with the dominant allele for tall and the recessive allele for the short gene.
Recessive alleles are only expressed in the phenotype if the organism is homozygous for the recessive allele (assuming diploidy). If the trait is sex-linked, then it will always show up in males if passed.
there is neither a "black skin" allele nor a "white skin" allele. skin color is accountable to myriads of factors & not attributable to a single gene. perhaps this question comes out from an attempt to guess the shade of a mixed-race child. simply put, there is no telling what color a child will come out. sometimes more of the father's complexion will show; othertimes vicer-versa.
This question is worded weird, because if someone had a dominant phenotype, as in Brown eyes dominant, than they would be BB or Bb. The exact genotype would need to have a key to what one of their parents' genotype was. Example: If a man with brown eyes (dominant) had a mom with blue eyes (recessive) then what would the man's genotype be? the answer would be Bb because that means that the man's dad would have BB and mom would be bb and when using punnent square, his genotype is Bb (only possible genotype is Bb)
50%
50%AnswerColourblindness is a sex-linked recessive mutation i.e. the mutation is carried on the X chromosome. If a colour blind man married a carrier woman they could produce a carrier daughter, a colour blind daughter, a normal son or a colour blind son. The probability of each phenotype occurring is 25%.If XC represents the normal allele for seeing colour and Xc represents the colour blind allele the genotypes of the possible offspring would be as follows:Carrier daughter = XCXcColour blind daughter = XcXcNormal son = XCYColour blind son = XcYThis information is incorrect. In fact a woman can be color blind. My mother is color blind as are my brothers. My sister and I are not though we carry the gene. I have two daughters and one is color blind and the other is not color blind.The information I gave is not incorrect - I have included the possibility of that 'mating' producing a colour blind female child.
It depends on the two alleles the man carries; if he is carrying HH- it is a 100% chance, because HD is autosomal dominant. If his allele is Hh, it is a 50% chance.
The female would have to have the blood genotype of AO. The recessive O is masked by the female with the domaint A allele. Their offsprings genotype would be BO the B would be from the father and the recessive O from the mother.