50%
Rr
Crossing between two parents is done to combine noble characters of parents into the next generation. Suppose a dwarf pea plant has better quality of pods and its tall counterpart has more number of pods per plant then a plant breeder may think of combining these two characters into its hybrid. The genotype for these tall & dwarf parents with variable pod quality and quantity may be designated as - Tall parent --- ppTT & dwarf parent -- PPtt
This would result in 1 heterozygous offspring. You can think of it like this: If the first parent is homozygous it would have AA alleles, the second heterozygous parent would be AB. When they mix genetically it would result in 4 combinations: AA, AA, AA, AB. As there is only one B there can only be one heterozygous offspring. This is not expected it is certain.
1:1:1:1:1:1:1:1 ratio is the expected outcome of a heterozygous (BbGgCc) and a homozygous recessive (bbggcc) cross.
In a monohybrid cross with one parent homozygous dominant and the other homozygous recessive The phenotype of the F1 offspring will be 100% that of the parent with the dominant allele. A cross of two of the F1 offspring will be 75% phenotypically like the dominant allele and 25% will be hommozygous recessive or 3 to 1
1 homozygous dominant: 2 heterozygous: 1 homozygous recessive
In the P generation, one parent is homozygous dominant and the other parent is homozygous recessive. In the F1 generation, the product of a cross between the P generation, the offspring are all heterozygous. In the F2 generation, the product of a cross between the F1 generation, the expected result is 1/4 homozygous dominant, 1/2 heterozygous, and 1/4 homozygous recessive.
In the P generation, one parent is homozygous dominant and the other parent is homozygous recessive. In the F1 generation, the product of a cross between the P generation, the offspring are all heterozygous. In the F2 generation, the product of a cross between the F1 generation, the expected result is 1/4 homozygous dominant, 1/2 heterozygous, and 1/4 homozygous recessive.
The expected phenotype for a Mendal F1 monohybrid cross is 3:1. Looking at heterozygous parents (F1) who share the same dominant trait, e.g. Straight tail.Crossing two heterozygous parents from the F1 generation results in an F2 generation that produces a 75% chance for the appearance of the dominant phenotype, of which two-thirds are heterozygous, and a 25% chance for the appearance of the recessive phenotype, giving the ratio 3;1.Inheritance pattern of dominant and recessive phenotypes when each parent is homozygous for either the dominant or recessive trait. All members of the F1generation are heterozygous and share the same dominant phenotype, while the F2generation exhibits a 3:1 ratio of dominant to recessive phenotypes.
If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.
Rr
Crossing between two parents is done to combine noble characters of parents into the next generation. Suppose a dwarf pea plant has better quality of pods and its tall counterpart has more number of pods per plant then a plant breeder may think of combining these two characters into its hybrid. The genotype for these tall & dwarf parents with variable pod quality and quantity may be designated as - Tall parent --- ppTT & dwarf parent -- PPtt
Make a Punnet Square:White HETEROZYGOUS---WwRed HOMOZYGOUS--ww (this one is recessive because the white characteristic dominated in the heterozygous type)So:W ww Ww www Ww wwThese four are the potential types of the offspring, they will either be HETEROZYGOUS WHITE or HOMOZYGOUS RED, no homozygous white
This would result in 1 heterozygous offspring. You can think of it like this: If the first parent is homozygous it would have AA alleles, the second heterozygous parent would be AB. When they mix genetically it would result in 4 combinations: AA, AA, AA, AB. As there is only one B there can only be one heterozygous offspring. This is not expected it is certain.
1:1:1:1:1:1:1:1 ratio is the expected outcome of a heterozygous (BbGgCc) and a homozygous recessive (bbggcc) cross.
Let T=trait (dominant) Let t= trait (recessive) Father has Tt and mother also has Tt The possible combinations for offspring are: TT Tt Tt and tt Therefore There is a 3/4 change of the offspring having the dominant trait and a 1/4 Chance of the offspring having the recessive trait It should also be noted that there is a 1/4 chance of the offspring carrying two dominant genes meaning that any of their children will also share the dominant trait
If the lethal gene is recessive, and the parent carrying it is heterozygous for that gene, it can be passed down to offspring in the recessive form. If the mate of the parent happens to be carrying the same gene heterozygously, 50% of offspring will be expected to inherit the recessive lethal gene heterozygously. 25% of the offspring will be expected to inherit the lethal gene homozygously, leading to death. The remaining 25% of offspring we will expect to homozygously inherit the non-lethal gene. 1:2:1 ratio