You know that,
E = h*c/λ
Where
h = Plank's constant = 6,626 x 10-34 J*s
c = speed of light = 3*108 m/s
λ = greek letter lambda representing the wavelength =624nm => 6,24 *10-7m
and therefore [(6.626 X 10^-34 J) X (3 X 10^8 m/s)] / (6.24 x 10^-7) = 3.18 x 10^-19 ... That should be right!
Using velocity = frequency * wavelength, and noting that all Electromagnetic waves have a speed of 3.0 * 108 , the frequency of the light is 1.2 * 1015 Hz.
The energy of a photon with a frequency, f, is given by Energy = fh; where h is the Planck's constant. Substituting values of f and h(= 6.26 * 10-34) , the energy of the photon is found to be 7.512 * 10-19 J.
2.93x10^-19 Joules first use the v=c/h formula to find frequency then use the energy formula to find energy.
- frequency of this light : c=ln, so n=c/l (and remembering that 1 nm = 1 x10-9 m) = (3.00 x 108 m/s)/554x 10-9 m) = 5.42 x 1014 1/s - the energy of a photon of this light: E(photon) = hn = (6.6262 x 10-34 J·s)(5.42 x 1014 1/s) = 3.59 x 10-19 J
In the spectrum of electromagnetic radiation the wave property that changes is the frequency. So for example xrays have higher frequency then blue light which has higher frequency then red light which has higher frequency then radio waves etc.
photon
A photon is a fundamental or elementary particle and the carrier of the electromagnetic field. In this light (no pun intended) it can be applied to all electromagnetic energy, including radio waves. There wouldn't be a "lowest frequency" of electromagnetic radiation that was not photonic. ---- ...or if there was it would have a wavelength the size of the Universe : ) Couldn't carry a whole lot of data there...
The energy of this photon is 3,7351.10e-19 joules.
The energy of the photon is 3,1631.e-19 joule.
1.11 atto Joules.
Photon Energy E=hf = hc/w thus wavelength w= hc/E or the wavelength is hc divided by the energy of the photon or w= .2 e-24 Joule meter/Photon Energy.
3.84 x 10-19 joules.
2.93x10^-19 Joules first use the v=c/h formula to find frequency then use the energy formula to find energy.
Joules is a unit of energy; watts is a unit of power. You can't just convert it. The relationship between the two is: power = energy / time in units: watts = joules / second
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
It depends on the wavelength of the photon. Energy of each photon is hc/λ, where h = Planck's constant = 6.626x1034 Js, c = speed of light = 3x108 m/s, and λ = wavelength of the photon
For the frequency, first convert the wavelength to meters (divide the number of Angstroms by 1010), then use the formula: wavelength x frequency = speed. Using the speed of light in this case. Solving for frequency: frequency = speed / wavelength. To get the photon's energy, multiply the frequency times Planck's constant, which is 6.63 x 10-34 (joules times seconds).
You have to multiply the joules/photon by Avogadro's Number, i.e., by the number of particles in a mole.
Twice the energy means twice the frequency, and therefore half the wavelength.