DRAM
Rimm
16bit refers to the number of bits that can be used in a single data format element. 16bit graphics are found in games that can be played on the original Nintendo Entertainment System console.
Standard VGA is 16bit.
Its 16bit microprocessor,and-> the 8086 has a 16bit databus 20bit address bus-> the intel 8086,is designed to operate in two modes namely(1) minimum mode(2) maximum mode
The Java compiler itself (javac) is a 32-bit application.
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
so they fit correctly into an 8bit or 16bit slot
A 128 KB memory can be segmented into blocks using 16-bit address lines by leveraging the addressable memory space defined by those lines. With 16 bits, you can address up to 2^16 (or 65,536) unique addresses, which corresponds to 64 KB of memory. To accommodate the full 128 KB, the memory can be divided into two segments of 64 KB each, allowing the system to reference the blocks efficiently. Thus, the memory can be organized into blocks, with each block containing 64 KB and addressed via the 16-bit lines, typically using techniques like paging or segmentation for management.
Sorry, but no. Genesis only plays 16bit games.
As it is 16bit processor it can manupulate 16 bits in one operation
16 bits per block . 8 16bit blocks = 128bits
20 kHz is not a particularly high sampling rate - it only reproduces sounds up to 10 Khz, and even senior citizens can hear that. The correct answer to the question is 4,800,000 Bytes.