39 m\s downward
They will both have the same speed because the will hit the ground at the same time, due to vertical velocity.
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.
they hit the ground at same instant
initial velocity of the kick = 28.06 m/s
no because the ball is round and it would make no difference in what side you put it on because it has no sides
They will both have the same speed because the will hit the ground at the same time, due to vertical velocity.
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.
The volleyball will NOT hit the ground with greater anything. Assuming that the soccer ball is the same spherical diameter and greater mass than the volleyball it will hit the ground with greater velocity and greater impact.
they hit the ground at same instant
31 m/s
initial velocity of the kick = 28.06 m/s
it strikes the ground at a velocity of 17.9 ft/s
Use the mechanics formula Final velocity = initial velocity + acceleration * change in time 4m/s = 0 + (9.8 m/s²)t t = 0.41s distance = initial velocity * time + 1/2 accel * time² = 1/2(9.8m/s²)(0.41s)² = 0.82m
no because the ball is round and it would make no difference in what side you put it on because it has no sides
both reaches the ground at the same time because in the moon there occurs free fall.
Ignoring any effects due to air resistance, the speed of the stone is zero at the instant it's dropped, and increases steadily to 78.98 meters per second when it hits the ground. The velocity is directed downward throughout the experiment.
Let v be the velocity when the ball is at 640 feets going downwards v = 48 feet /sec let the velocity with which it reaches the ground be u then, u2=v2+2gh g = acc due t ogravity in feet/sq.sec h = 640 feet the time taken to reach the ground = time to return to 640ft + the time to fall from there Time taken to get to the ground is 8 seconds. Final velocity is 208 feet per second downwards