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A speed boat moving at a velocity of 25 m/s runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its rate of deceleration?
James Schwerdtfeger
0.14 m/s²
Anonymous
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If a car moving at an initial velocity of 19 meters per sec has a stopping distance of 31 meters what is the magnitude of its acceleration?
Average speed during the deceleration is 1/2(19 + 0) = 9.5 meters per second.Time of deceleration is (31 / 9.5) seconds.Magnitude of deceleration is (change of speed) / (deceleration time) = 19 / (31/9.5) = (19 x 9.5) / 31 = 5.823 m/s2(The acceleration is the negative of this number.)
A ball thrown up vertically returns to the thrower after 6 seconds find the velocity with which it was thrown up?
The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward
What is the velocity of a bicycle in meters per second if it travels 1 kilometers west in 4.1 minutes?
1 kilometer is equal to 1000 meters. 4.1 minutes is equal to 246 seconds. Velocity would equal 1000 meters divided by 246 seconds. So the answer is 4.065 meters per second West.
What is acceleration and its si unit?
Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.Acceleration is the rate of change of velocity - how fast a velocity changes. Therefore, its units are naturally (meters/second) / second, usually written as meters/second2.
Why the time twice in unit acceleration?
An acceleration is not a velocity - it is the rate of change of velocity. In SI units, the units of velocity are meters/second. Acceleration is the rate of change of velocity, per unit time - how fast the velocity changes. Therefore, its units are velocity / time. In SI units, this gives you (meters/second) / second, usually written as meters/second2.
A speed boat is moving at a velocity of 25 ms runs out of gas and drifts to a stop 3 minutes later 100 meters away What is the rate of deceleration?
0.14
What is the rate of deceleration for a speed boat moving at a velocity of 25 meters per second which runs out of gas and drifts to a stop 3 minutes later 100 meters away?
0.14 m/s2 A+
What is the deceleration of a car traveling with a velocity of 30 meters per second slowing down to a velocity of 10 meters per second within 10 seconds?
you doing homework???
If a car moving at an initial velocity of 19 meters per sec has a stopping distance of 31 meters what is the magnitude of its acceleration?
Average speed during the deceleration is 1/2(19 + 0) = 9.5 meters per second.Time of deceleration is (31 / 9.5) seconds.Magnitude of deceleration is (change of speed) / (deceleration time) = 19 / (31/9.5) = (19 x 9.5) / 31 = 5.823 m/s2(The acceleration is the negative of this number.)
What is deceleration measured in?
Deceleration means to decrease the velocity. The SI unit is the same as acceleration. In SI units, acceleration is measured in meters/second² (m·s-2).
When throwing a ball straight up when in the air with an initial velocity of 10 meters per second what high will it go and how long will it take to return to the ground?
The initial velocity is 10 meters/sec and is thrown up against the gravitational pull of the earth. This means that the ball is experiencing a deceleration at the rate of 9.8 meters/sec/sec to bring its final velocity to zero. v^2 - u^2 = 2gs where u is the initial velocity, v the final velocity, g is the acceleration or deceleration, and s is the distance traveled. 0^2 - 10^2 = 2 x (-9.8) x s -100 = -19.6s 100 = 19.6s s = 100/19.6 = 5.102 meters Now v = u + gt where v is the final velocity, u is the initial velocty, g is the acceleration or deceleration, and t is the time. When the ball is thrown up with 10 meters/sec velocity it is acted upon by the deceleration of gravity until its velocity becomes zero. So 0 = 10 - 9.8t or 9.8t = 10 t = 1.020 seconds The time for the ball to go up is 1.020 seconds and the same time is taken for the ball to come back for a total of 2.040 seconds.
A ball thrown up vertically returns to the thrower after 6 seconds find the velocity with which it was thrown up?
The velocity changes from [ V upward ] to [ V downward ].The total change in velocity is [ 2V ].Acceleration = (change in velocity) divided by (time for the change) = 2V/6But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .9.8 = 2V / 62V = 58.8V = 29.4 meters per second upward
What is the velocity of a bicycle in meters per second if it travels 1 kilometers west in 4.1 minutes?
1 kilometer is equal to 1000 meters. 4.1 minutes is equal to 246 seconds. Velocity would equal 1000 meters divided by 246 seconds. So the answer is 4.065 meters per second West.
Max jogged 80 meters north in 10 minutes what was his velocity?
80/10 = 8 metres per minute
How do you find the average velocity in ms of a bicycle that starts 150 meters north of town and is 1200 meters north of town in 30.0 minutes?
You divide the distance traveled by the time.
Scooter acquires a velocity of 36 kilometre per hour in 10 seconds after the start it takes 20 seconds to stop calculate the acceleration?
To find the acceleration, we need to first convert the velocity from kilometers per hour to meters per second. 36 kilometers per hour is equivalent to 10 meters per second. Next, we can use the formula for acceleration: acceleration (a) = change in velocity (Δv) / time taken (Δt). For the acceleration during the start, the change in velocity is 10 m/s (initial velocity was 0) and the time taken is 10 seconds. Thus, the acceleration is 1 m/s^2. For the deceleration (when stopping), the change in velocity is -10 m/s (final velocity was 0) and the time taken is 20 seconds. Thus, the acceleration is -0.5 m/s^2. Negative sign indicates deceleration.
What is the velocity when falling 1000 meters?
Ther velocity when falling 1000 meters is v=sqroot(2x1000x9.8) = 140 meters/second.
