As long as the object stays somewhere near the surface of the earth, the acceleration due to gravity is constant, whether the object is moving up, down, sideways, or not moving at all.
Here on Earth, the vertical acceleration of any projectile is -9.81ms-2. The minus sign shows that they accelerate downwards. This is true for an object dropped from a height, however the question refers to a projectile, which implies an object that has been launched by a mechanism. It thus has both a horizontal and a changing vertical acceleration in addition to the constant downward gravitational acceleration. A general solution can be found in the related link. (Or by studying the pages in your textbook assigned by your teacher.)
You haven't told us anything about the object, how fast it was launched,whether it was launched straight up or at an agle, and on what planet thiswhole event occurred. So we have to assume reasonable choices for allof these details ... that is, make them up.We're going to assume that it happened on Earth, the object was a baseball,it was launched at a speed of 17.8816 meters per second, aimed at a preciseangle of exactly (0.2718 pi) radians above the horizontal. We're also going toignore any effects that air resistance may have on its motion.The acceleration of gravity on Earth is 9.8 meters (32.2 feet) per second2,directed downward. From the instant the ball leaves your hand until it hitsthe ground, that is its acceleration. All the way up, at the very top of itspath, and all the way down. No matter how big it is, how heavy it is, whatspeed it was tossed with, or in what direction. Doesn't matter.It's speed will change and depend on all of the details, and its velocity will changeand depend on all the details. But its acceleration won't.
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
The question is describing something more like a cannonball than a rocket.The mass of a rocket is continually decreasing as the fuel load is burned.The object in the question has a constant volume, so it might as well be abullet or a rock.Once we notice that, we realize that the question is nothing but a medieval misconceptiondressed up in a space-age suit ... the notion that heavy objects run out of oomph soonerthan light ones do when launched vertically, and that the heavier ones then fall backfaster than the lighter ones.In fact, it makes no difference what the mass of the projectile is. Shot vertically ata speed of 28.5 meters per second, the speed of a stone or a battleship slows by9.8 meters per second every second ... the acceleration of gravity. So it continues torise for (28.5/9.8) = 2.908 seconds .The speed at the bottom is 28.5 m/s. The speed at the top is zero.The average speed before it reaches the top is (28.5/2) = 14.25 m/s.The distance traveled from the bottom to the top is (14.25) x (2.908) = 41.44 meters .The purist will object that our result cannot be accurate. because the thing has beenlaunched vertically, directly away from the center of the earth, and the accelerationof gravity steadily decreases as our projectile rises. We welcome the purist's objection,and we shall deal with it in the Appendix.==============================================Appendix.The acceleration of gravity decreases with altitude from the earth's surface, sothe accuracy of our conclusion must be tested by sampling the acceleration ofgravity in the first 42 meters above the surface.The acceleration of gravity is inversely proportional to the projectile's distancefrom the center of the earth.Earth equatorial diameter = 12,756 Km.Radius = 6,378 km.Relative gravity at 42 meters' altitude = (6,378 / 6,378.042)2 = 0.9999868 .Since we only used a single decimal place for the acceleration of gravity altogether,and had no intention of pursuing anything to to the fifth place, we felt justified inignoring a variation in gravity of this magnitude.
As Galileo demonstrated, acceleration is independent of mass, therefore, they would reach terminal velocity at the same time. This is, of course, ignoring air friction.
Because the fuel tank is attached to the bottom of the rocket --That's a terrible answer.
The only force acting on a projectile once launched is gravity. So the acceleration of any object launched at any angle is the acceleration due to gravity, -9.8m/s2.
If it were accelerating due to gravity it would be vectoring down.
You can't unless you know gravity and air pressure as well.
I think so. The acceleration of a 3¢ Chinese pop-bottle rocket is probably not the same as the acceleration of the Saturn-V booster that launched the Apollo vehicles.
The idea here is to use Newton's Law, F=ma. Solving for acceleration: a = F/m. The number of seconds is irrelevant if all you want to calculate is the acceleration.
Melissa J. B. Rogers has written: 'Acceleration studies' -- subject(s): Acceleration (Mechanics) 'Summary report of mission acceleration measurements for STS-62, launched March 4, 1994' -- subject(s): Accelerometers, Acceleration (Physics), Space shuttle missions, Microgravity, Spacecraft environments 'Summary report of mission acceleration measurements for STS-65, launched July 8, 1994' -- subject(s): Center of mass, Microgravity, Earth orbital environments, Centrifuges, Accelerometers, Physical exercise 'Summary report of mission acceleration measurements for STS-66, launched November 3, 1994' -- subject(s): Acceleration (Physics), Crew experiment stations, Infrared telescopes, Microgravity, Postflight analysis, Protein crystal growth, Space shuttle missions, Space shuttle payloads, Space transportation system flights, Spaceborne experiments
Launch Pad - it is shot off to space vertically with SRB (solid rocket boosters) - havent you seen om TV - shuttle being launched??
Normally you would weigh the most on a boat. However, you would weigh more on a space shuttle while it is ascending while being launched.
A geostationary satellite must orbit in the plane of the equator to be stationary. If launched from the equator it is already in that plane and only needs enough fuel to lift it and inject it into the right orbit. If launched from another point it will need extra fuel for maneuvering from its initial orbital plane into the equatorial plane. This gets worse with greater initial orbital inclination.
Because the bomber is moving quickly, which means that the bomb is travelling quickly forward when it is launched. This would take the bomb way past the target by the time it reaches the ground.
The first objects in space (going by the Karman line definition of outer space, being at 100km altitude from sea level) were the German V-2 rockets during WWII. Their purpose was to bomb allied cities. The first one to actually reach space was on Oct 3, 1942. However many V-2s did not pass the 100km mark because most were not launched vertically. When launched vertically, such as in testing, they reached a maximum of 208km in altitude. Funny how war seems to be the driving force behind innovation.