I'll get it started, but this is a complicated question. Assuming this is an autosomal trait, and assuming it only has one gene, and assuming it causes death before reproductive age: In order for someone to develop the phenotype, both parents have to be carriers. So, for the 1 out of 100,000 child born with the disease, you had to have 2 carriers mate. But there were more than 2 carriers in the 100,000. How many carriers do you have to have for 2 of them to mate? For that, you'd have to know how many people out of a population of 100,000 actually mate in the first place. You'd also have to know the average number of children resulting from a union. Let's say 75% of people mate, and the average number of children is 2. So of 100 people, 75 mate. But each union involves 2 people, so there are actually 37.5 pairings, producing 37.5 x 2 = 75 children. Now, assuming a frequency of carriers of F, what is the likelihood of 2 carriers mating? Let's say that everybody mates. So out of 100 people, there are 50 pairings. So the probability of mating with a carrier is approximately F.
Most genetic defects related to enzyme function are recessive because most are lethal and can only persist because heterozygote carriers can live to reproduce.
What kind of diseases are the most common genetic diseases? (For example, those in which both parents may be carriers of the disease without knowing it because they don't actually have the disease.)
It is positive and negative signal in the frequency of wave form, the voltage of amplitude modulation, that carriers the signal of frequency.In the process of graph showing result ...
Many negative diseases and traits are very rare and recessive. In a population where very little inbreeding occurs, these negative traits do not show up frequently because such a small percent of the population is a carrier for them. When related individuals who are carriers of these negative recessive traits breed with each other, their offspring receive two copies of the trait, resulting in the physical or mental retardation of the offspring due to the negative trait.
autosomal dominant is only when one allele is messed upautosomal recessive is when you give the disease to your child 50/50 chance.Not true.... 50/50 when its Autosomal Dominant(see below)Recessive InheritanceBoth parents carry a normal gene (N), and a faulty, recessive, gene (n). The parents, although carriers, are unaffected by the faulty gene. Their offspring are affected, not affected, or carriers. This type of inheritance was first shown by Mendel.Dominant InheritanceOne parent has a single, faulty dominant gene (D), which overpowers its normal counterpart (d), affecting that parent. When the affected parent mates with an unaffected and non-carrier mate (dd), the offspring are either affected or not affected, but they are not carriers.
I don't know and don't care
I don't know and don't care
recessive
Sickle cell anemia is an autosomal recessive disorder. It can result from two carriers having a child together.
Yes II - 1 and II- 2 are carriers. They have a dominant trait but have a child with a recessive trait. They must be carriers.
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Bassen-Kornzweig syndrome is inherited as an autosomal recessive disorder, which means that parents of affected individuals are themselves unaffected carriers, and that they have a 25% risk of having an affected child.
Aa. This is the heterozygous condition. Two alleles, one of which is dominant and masks the expression ( to varying degrees ) of the other allele. 'A' dominant and 'a' recessive. So, if the trait in question is the recessive allele the dominant allele masks its expression and the organism is a ' carrier ' of the trait and can pass it on to progeny.
individuals that are heterozygous for alleles
carriers
Sickle cell anemia is an autosomal recessive disease. Carriers have sickle cell trait, which confers resistance to malaria.
game and food problem are Main cause of scoliosis so this carriers' are so bright