Genetically speaking, there are roughly 8 well known 'Brown' mice. They all have different genes, which creates different shades. You should probably find out what shade of brown this 'Brown' mouse in question is.
There is only one type of Black genetic colouring in mice.
Generally speaking, if we were just using the common Agouti brown mouse (wild colour) & crossed it to Black, then the entire litter should've resulted in Agouti mice. However, Agouti being represented by a dominant A-, & the Black being represented by a recessive AA, crossing A- to AA would result in an entire litter of Aa = Agouti carring Black.
If you crossed one of those offspring back to the Black parent, you would get Aa & AA in the litter, resulting in the litter being 50% black, 50% Agouti.
However, if the 'Brown' mouse wasn't Agouti, & was actually another brown called Chocolate (I'm serious), then crossing Black (which in this case will be BB) to Chocolate (bb) would result in an entire litter of Blacks carrying Chocolate (Bb) . If you crossed 2 of the offspring together, you would get a mix of Blacks & Chocolates.
NB: Black is a dominant gene to all other genes but Agouti.
Ablack stool can also be caused by a serious condition, such as bleeding in the digestive tract caused by a peptic ulcer
the offspring will have both black and whit feathers.
When iodine solution is mixed with starch solution they produce blue-black color.
To determine the genotype of a white ram, breed him with black females. Black females are homozygous recesive for the black trait, a. If the ram is homozygous dominant, all offspring will be white (and heterozygous). If the ram is heterozygous, approximately half of it's offspring will be white and half will be black.
B is dominant.
Yes
Its called budding.
No, rattlesnakes and rat snakes cannot interbreed.
Ablack stool can also be caused by a serious condition, such as bleeding in the digestive tract caused by a peptic ulcer
No, not always. The offspring can be white, black, black and white or shades of both.
This is an example of incomplete dominance.
none black bears have no offspring in one year
the average offspring of a bear is 2. But the offspring depends on the species.
The offspring are black feathered because the black feather gene is dominant
It is adaption because you need to adapt to certain areas SO your offspring's can survive its the same as in if all of a sudden the world was cove rd in snow and there were 1000,0000 white rabbits and 20000.00000000 black rabbits the black rabbit population would decrees because the rabbits need to adapt to the environment to protect it self from predator's.
If you crossed a black hen/roo with a white hen/roo, the offspring would NOT be blue. If he was recessive white, the chicks would be black. If he was dominant white, the chicks would be white with some black "smudges" or "spots". The only way to produce 100% blue chicks is to cross a black roo over splash hens or a splash rooster over black hens.
the black widow or somthing else but im prety sure