1.3 Å= 1.3 x 10-10 m C=λv 3.00 x 108 m/s = 1.3 x 10-10 m (v) v= 2.3 x 1018 Hz E=hv E= 6.626 x 10-34 J (sec) x (2.3 x 1018 1/sec) E= 1.5 x 10-15 J
1.3 Å= 1.3 x 10-10 m C=λv 3.00 x 108 m/s = 1.3 x 10-10 m (v) v= 2.3 x 1018 Hz E=hv E= 6.626 x 10-34 J (sec) x (2.3 x 1018 1/sec) E= 1.5 x 10-15 J
4.2 x 10^16 photons
Gamma rays have the most energy per photon.
The energy of this photon is 3,7351.10e-19 joules.
In our Universe, EM radiation can only come in discrete chunks called "photons." The energy of each individual photon depends on the frequency of the EM radiation. Frequency depends on wavelength (or vice-versa): the shorter the wavelength, the higher the frequency. Thus, short wavelength photons have more energy. That's just how our Universe operates, whether or not we like it.
assuming the wave is electromagnetic... the energy of a single photon of that frequency is given by the formula E=hf where E= energy of the photon h=the Planck constant f= the frequency of the photon From this the energy of the photon is the Planck constant (6.63 x10-34) multiplied by the frequency 3.6x1016 Hz. E= 23.9x10-18 Joules. The wavelength of any wave is determined by the equation wave speed = frequency x wavelength. thus, the wavelength is the wave speed divided by the frequency. since all electromagnetic waves travel at the speed of light then... wavelength = 3x108 / 3.6x1016 wavelength = 0.83x10-8 = 8.3x10-9 metres. The electromagnetic radiation corresponding to this energy and wavelength is ultraviolet radiation and may be of interest to nuclear medicine.
Energy is equal to Planck's constant times the speed of light divided by the wavelength of the light. E=h*c / lambda. So the electromagnetic radiation with the largest wavelength will correspond to the lowest energy. Since radio waves have the largest wavelength (about 1,000m) they will have the lowest energy!
The energy of the photon is 3,1631.e-19 joule.
A photon of this wavelength has an energy of about 10 ^ -5 eV.
Photon Energy E=hf = hc/w thus wavelength w= hc/E or the wavelength is hc divided by the energy of the photon or w= .2 e-24 Joule meter/Photon Energy.
Gamma rays have the most energy per photon.
The energy of this photon is 3,7351.10e-19 joules.
The energy of one photon is given by its frequency X planck's constant Its frequency is given by the speed of light divided by the wavelength.
The energy in each photon (quantum) of electromagnetic radiation is(h) x (c) / (wavelength)h = Planck's Konstantc = speed of light
After the absorption, the matter has added energy equal to 'hf' the energy of the absorbed photon.
This is true. Each photon carries more energy when it has shorter wavelength / higher frequency.
Remember that for any wave, wavelength x frequency = speed (of the wave). So, as the wavelength increases, the frequency decreases. Also, since the energy of a photon is proportional to the frequency, the energy will decrease as well in this case.
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
... frequency of the electromagnetic radiation of which the photon is a particle.