Al(NO3)3 + 4NaOH -> NaAlO2 + 3NaNO3 + 2H2O
2 NaOH + SO2 = H2O + Na2SO3
Mn(CH3COO)2 + 2NaOH ----> Mn(OH)2 + 2CH3COONa
2 KOH + H2CO3 = 2 H2O + K2CO3
2(NH4)3PO4 + 3Ba(OH)2 --> 6NH4OH + Ba3(PO4)2
There are to possible reactions depending on the relative amounts of each substance. If there is an abundance of sodium hydroxide the balanced equation will be: 2NaOH + H2CO3 --> 2H2O + Na2CO3 If there is more carbonic acid: NaOH + H2CO3 --> H2O + NaHCO3
2 Al + 6 H2O > 2 Al(OH)3 + 3 H2 Al(OH)3 + NaOH > Na+ + [Al(OH)4]- __________________________________________________________________ 6H2O(l)+2Al(s)+2NaOH(aq)--------------- 2NaAl(OH)4(aq)+3H2(g)
the chemical equation of aluminium and iodine is given a s follows :2Al +3 I -> Al 2 I 3.This is a balance eqaution .
is this equation correct? CH3CH2COOH + NaOH --> CH3CH2COONa +H2O
2caoh + 2h2so4_2caso4 + 3h2o the equation is balance
The chemical equation is:Al2(SO4)3 + 3 Mn = 2 Al + 3 MnSO4
2 NaOH + SO2 = H2O + Na2SO3
Aluminium + Lead Chloride --> Aluminiu, Chloride + Lead Al + 3PbCl --> AlCl3 + 3Pb
Mn(CH3COO)2 + 2NaOH ----> Mn(OH)2 + 2CH3COONa
3koh + h3po4 --> k3po4 + 3h2o ======================== ( site messing up again!! All letters capitalized )
Calcium Hydroxide + Hydrochloric Acid → Calcium Chloride + Water Ca(OH)2 + 2HCl → CaCl2 + 2H2O
2 KOH + H2CO3 = 2 H2O + K2CO3
2(NH4)3PO4 + 3Ba(OH)2 --> 6NH4OH + Ba3(PO4)2