What is the balance equation for chemical reaction of aluminium with sodium hydroxide?

Answer 1

2 Al + 6 H2O > 2 Al(OH)3 + 3 H2

Al(OH)3 + NaOH > Na+ + [Al(OH)4]-

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6H2O(l)+2Al(s)+2NaOH(aq)--------------- 2NaAl(OH)4(aq)+3H2(g)

Answer 2

Normal word equation:

Aluminium (s) + sodium hydroxide (?) ----> aluminum hydroxide (aq) + sodium (s)

Normal equation:

Al + NaOH -----> AlOH + Na

Balanced equation:

Al + NaOH ------> AlOH + Na

Answer 3

A small quantity of aqueous sodium hydroxide forms white gelatinous precipitate of Aluminium hydroxide which on reacting with excess sodium hydroxide forms a soluble salt Sodium aluminate.

AlCl3 + 3NaOH = Al(OH)3 + 3NaCl

Al(OH)3 + NaOH = NaAlO2 + 2H2O

Answer 4

The balanced chemical equation for the reaction of aluminum with sodium hydroxide is: 2Al(s) + 6NaOH(aq) → 2Na3AlO3(aq) + 3H2(g)

Answer 5

aluminium hydroxide (aqueous) and if there is excess sodium hydroxide, sodium aluminate is formed as aluminum is an amphoteric metal.

Answer 6

Although it wouldn't actually react, the only possible products are sodium and aluminium hydroxide.

Answer 7

If the sodium hydroxide is in concentrated solution in water, the most likely reaction is

2 Al (s) + 2 NaOH (aq) + 2 H2O = 2 NaAlO2 (aq) + 3 H2 (g).

Answer 8

Al2O3 + 6NaOH --> 2Al(OH)3 + 3Na2O

As you can see, when aluminium oxide reacts with sodium hydroxide, aluminium hydroxide and sodium oxide are produced.

Answer 9

2Al + 2NaOH + 6H2O → 2NaAl(OH)4 + 3H2

Answer 10

yes it does