Sulfur is generally S8.
S8 + 8 O2 → 8 SO2
The equation for the burning of sulfur in the presence of oxygen to produce sulfur dioxide is: S (sulfur) + O2 (oxygen) --> SO2 (sulfur dioxide).
The balanced equation for the burning of carbon in air is: C + O2 -> CO2. This equation shows that one molecule of carbon reacts with two molecules of oxygen to produce one molecule of carbon dioxide.
The blank would be filled with "oxygen" because fossil fuels burn in the presence of oxygen to produce carbon dioxide and water. The balanced equation for burning fossil fuels is: CxHy + O2 → CO2 + H2O.
The balanced equation for ethanol (C2H5OH) burned in air is: C2H5OH + 3O2 -> 2CO2 + 3H2O. This equation shows that ethanol reacts with oxygen to produce carbon dioxide and water.
The balanced symbol equation for glucose is C6H12O6 + 6O2 → 6CO2 + 6H2O. This equation represents the process of cellular respiration, where glucose is oxidized to produce carbon dioxide, water, and energy.
The equation for the burning of sulfur in the presence of oxygen to produce sulfur dioxide is: S (sulfur) + O2 (oxygen) --> SO2 (sulfur dioxide).
The balanced equation for the burning of carbon in air is: C + O2 -> CO2. This equation shows that one molecule of carbon reacts with two molecules of oxygen to produce one molecule of carbon dioxide.
The blank would be filled with "oxygen" because fossil fuels burn in the presence of oxygen to produce carbon dioxide and water. The balanced equation for burning fossil fuels is: CxHy + O2 → CO2 + H2O.
The balanced symbol equation for glucose is C6H12O6 + 6O2 → 6CO2 + 6H2O. This equation represents the process of cellular respiration, where glucose is oxidized to produce carbon dioxide, water, and energy.
The balanced equation for ethanol (C2H5OH) burned in air is: C2H5OH + 3O2 -> 2CO2 + 3H2O. This equation shows that ethanol reacts with oxygen to produce carbon dioxide and water.
The symbol equation for burning a fuel such as methane (CH4) in oxygen (O2) to produce carbon dioxide (CO2) and water (H2O) is: CH4 + 2O2 → CO2 + 2H2O.
This balanced equation represents a combustion reaction, where a fuel (C4H10) reacts with oxygen gas (O2) to produce carbon dioxide (CO2) and water (H2O).
CH4 + 2O2 -> 2H2O + CO2. This balanced chemical equation represents the combustion of methane (CH4) with oxygen (O2) to produce water (H2O) and carbon dioxide (CO2).
If there is an excess of air, the reaction should produce diphosphorus pentoxide as its only product. If additionally the phosphorus molecule is simply a phosphorus atom, the balanced equation is: 4 P + 5 O2 -> 2P2O5. If phosphorus is considered to form a tetraatomic molecule, the equation would be: P4 + 5 O2 -> 2 P2O5
The balanced equation for the complete oxidation of acetylene (C2H2) burning in air is: 2C2H2 + 5O2 -> 4CO2 + 2H2O. This equation shows that two molecules of acetylene react with five molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.
The equation is CS2 + 3 O2 -> CO2 + 2 SO2.
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O