The easiest way to remember how to solve combustion reactions is to know that CO2 and H2O are always the two resulting products. Energy is the third and final product however for the purposes of this question it is not necessary. The other valuable piece of information is that other than your fuel source, C5H12, you will need O2 to manipulate your rich/lean ratio. To balance the equation first write out the the reactants and the products....C5H12 + O2 ----> CO2 + H2O and now balance by starting with Carbon on the left. Five on the left then five on the right. Next move to Hydrogen on the left, twelve on the left then 6 on the right. 6*2=12 total Hydrogens on the right. When you get to O2 you should just add up the total Oxygen on the right and divide by two and you will have your answer. 10+6=16/2=8 C5H12 + 8O2 ----> 5CO2 + 6H2O If you follow these steps you cannot logically fail.
it is balanced
=> 3co2 + 4h2o
C4h8 + 6 o2 = 4 co2 + 4 h2
2c + o2---2co
The chemical equation is:2 SO2 + O2 = 2 SO3
C2H6S PLUS O2 into CO2 plus H2O plus SO2
Balanced Equation: 2Mg(NO3)2 = 2MgO + 4NO2 + O2
Al + O2 will never yield Fe2O3.
This simple equation is: 2H2 + O2 = 2H2O
2c + o2---2co
The chemical equation is:2 SO2 + O2 = 2 SO3
C2H6S PLUS O2 into CO2 plus H2O plus SO2
Balanced Equation: 2Mg(NO3)2 = 2MgO + 4NO2 + O2
Al + O2 will never yield Fe2O3.
4P + 5O2 = 2P2O5
When it burns completely, each molecule of C4H8 becomes 4 molecules of CO2 and 4 molecules of H2O.
4Na + O2 --> 2Na2 + O
This chemical equation is:2 ZnS + 3 O2 = 2 ZnO + SO2
Cs2 + 3o2 ------->>> co2 + 2so2
2CO + O2 --> 2CO2