Solid sodium iodide reacts with water to form sodium ions and iodide ions. No further reactions occur because this compound is a salt of a strong acid and a strong base. Thus, the overall reaction is NaI(s)=> Na+ + I-
Sodium fluoride dissolves in water but does not chemically react with water.
A sodium iodide solution in water is obtained.
Sodium reacts with water to form sodium hydroxide and hydrogen. The balanced equation is 2Na + 2H2O --> 2NaOH + H2.
2Na+2H2O------>2NaOH+H2
water and the sodium salt
Sodium fluoride dissolves in water but does not chemically react with water.
A sodium iodide solution in water is obtained.
Sodium reacts with water to form sodium hydroxide and hydrogen. The balanced equation is 2Na + 2H2O --> 2NaOH + H2.
Na2O+H2O--->2NaOH
2Na+2H2O------>2NaOH+H2
2Na+2H2O------>2NaOH+H2
water and the sodium salt
2Na + 2H2O -> 2NaOH + H2
2Na + 2H2O = 2NaOH + H2
This equation is HCl + NaOH -> NaCl + H2O.
It is false; sodium iodide is more soluble than sodium chloride in water.
Sodium chloride is dissolved in water but doesn't react.