Solid sodium iodide reacts with water to form sodium ions and iodide ions. No further reactions occur because this compound is a salt of a strong acid and a strong base. Thus, the overall reaction is NaI(s)=> Na+ + I-
The balanced equation for cesium iodide is CsI(s) → Cs+(aq) + I^-(aq) when it is dissolved in water.
The balanced equation for sodium reacting with water is: 2Na + 2H2O → 2NaOH + H2
The balanced equation for the reaction of sodium oxide with water is: Na2O + H2O → 2NaOH
The reaction between ammonium iodide (NH4I) and sodium hydroxide (NaOH) will yield ammonia (NH3), sodium iodide (NaI), and water (H2O). The balanced chemical equation for this reaction is: 2NH4I + 2NaOH → 2NH3 + 2NaI + 2H2O
The molecular equation is6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2Oand the net ionic is6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O
The balanced equation for cesium iodide is CsI(s) → Cs+(aq) + I^-(aq) when it is dissolved in water.
The balanced equation for sodium reacting with water is: 2Na + 2H2O → 2NaOH + H2
The balanced equation for the reaction of sodium oxide with water is: Na2O + H2O → 2NaOH
The reaction between ammonium iodide (NH4I) and sodium hydroxide (NaOH) will yield ammonia (NH3), sodium iodide (NaI), and water (H2O). The balanced chemical equation for this reaction is: 2NH4I + 2NaOH → 2NH3 + 2NaI + 2H2O
The balanced chemical equation for the reaction of sodium with water is: 2Na + 2H2O -> 2NaOH + H2
The molecular equation is6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2Oand the net ionic is6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O
Sodium fluoride dissolves in water but does not chemically react with water.
Sodium reacts with water to form sodium hydroxide and hydrogen. The balanced equation is 2Na + 2H2O --> 2NaOH + H2.
The balanced equation for the reaction of sodium with water is: 2Na (s) + 2H2O (l) -> 2NaOH (aq) + H2 (g)
NaOH + HI <---> Na+ + I- + H2O <---> NaI + H2O
6NaOH + 3I2 = 5NaI + NaIO3 + 3H2O Six moles of sodium hydroxide and three moles of diatomic iodine yield five moles of sodium iodide, one mole of sodium iodate, and three moles of water. Cheers!
The balanced ionic equation for sodium chloride (NaCl) in water (H2O) is: NaCl (s) → Na+ (aq) + Cl- (aq) This equation shows the dissociation of sodium chloride into its ions sodium (Na+) and chloride (Cl-) in water.