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C plus plus program using function median that take three parameters of type double and returns the median of the three?
Wiki User
∙ 10y ago
There are several ways to implement this, however the basic principal is to sort the doubles in ascending order and return the middle element (in this case the 2nd element). The simplest implementation uses a 3-element array which is then sorted using an insertion sort, as shown in the following example.
#include<iostream>
#include<list>
double median(double& x, double& y, double& z)
{
// initialise the array
double a[3] = { x, y, z };
// sort the array
for(int i=1; i<3; ++i)
{
int hole=i;
int prev=hole-1;
double cur=a[hole];
while(hole && cur<a[prev])
{
a[hole]=a[prev];
--hole, --prev;
}
a[hole]=cur;
}
// return the middle element.
return( a[1] );
}
int main()
{
using namespace std;
double a, b, c;
a = 0.9;
b = 0.1;
c = 0.5;
cout<<"a="<<a<<endl;
cout<<"b="<<b<<endl;
cout<<"c="<<c<<endl;
cout<<"median="<<median(a,b,c)<<endl;
return(0);
}
Output:
a=0.9
b=0.1
c=0.5
median=0.5
It should be noted that when dealing with an even number of elements (such as 4 or 6), then there is no middle element, so you therefore need take the mean of the two middle elements instead. So if the sorted numbers are 0.1, 0.2, 0.5 and 0.9, then the median is the mean of 0.2 and 0.5, which is 0.35 (e.g., ( 0.2 + 0.5 ) / 2).
Wiki User
∙ 10y ago
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