C program for linear search using non recursive functiontion?

Answer 1

void main(){

int a[10],i,n,m,c=0;

clrscr();

printf("Enter the size of an array");

scanf("%d",&n);

printf("\nEnter the elements of the array");

for(i=0;i<=n-1;i++){

scanf("%d",&a[i]);

}

printf("\nThe elements of an array are");

for(i=0;i<=n-1;i++){

printf(" %d",a[i]);

}

printf("\nEnter the number to be search");

scanf("%d",&m);

for(i=0;i<=n-1;i++)

{

if(a[i]==m)

{

c=1;

break;

}

}

if(c==0)

printf("\nThe number is not in the list");

else

printf("\nThe number is found");

getch();

}

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Answer by Jatinder Pal Singh


#include
#include
void main()
{
clrscr();
int i,n,item,a[20];
printf("\nEnter no of elements=");
scanf("%d",&n);
printf("\nEnter %d elements=",n);
for(i=0;i{
scanf("%d",&a[i]);
}
printf("\nEnter the element to be search=");
scanf("%d",&item);
for(i=0;i{
if(a[i]==item)
{
printf("\n\t%d is present at position %d",a[i],i+1);
break;
}
}
if(i==n)
printf("\nElement is not Present");
getch();
}

Answer 2

#include<stdio.h>

#include<conio.h>

void main()

{

int a[7], i=0;

clrscr();

printf("Enter the elements of the array :");

for (i=0;i<=6 ;i++ )

{

scanf("%d\n", &a[i]); /* taking input array from the user */

}

printf("\nThe elements of the array you have enetered are as follows :")

for(i=0; i<=6; i++)

{

printf("%d", a[i]); /* printing the array elements or traversing the array */

}

getch();

}

Answer 3

Yes.