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Calculate the compressive stress in a 6 in diameter by 12 in high concrete test specimen if the total deformation under load is 0.015?
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A reinforced concrete column 200mm in diameter is designed to carry an axial compressive load of 300 kN Determine the required area of the reinforcing steel if the allowable stresses are 6 MPa?
600mm^2
Calculate the area of the ball with a diameter of 12 metres?
Calculate the area of the ball with a diameter of 12 metres
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Calculate the sum
How do you calculate radius from pipe diameter?
diameter = 2 * radius
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Double the Radius to Calculate the Diameter.
How do you calculate the compressive strength of concrete cubes?
Concrete specimens are tested using the ASTM39 Test Standard Test Methodfor Compressive Strengthof Cylindrical Concrete Specimens by using two samples made from the same test at the same age, usually at strength of 28 days old.Design engineers use the specified strength ƒ´c to design structural elements. This specified strength is incorporated in the job contract documents. The concrete mixture is designed to produce an average strength (ƒ´cr) higher than the specified strength, such that the risk of not complying with the strength specification is minimized.Cylindrical specimensfor acceptance testing should be 6 x 12 inch (150 x 300 mm) size or 4 x 8 inch (100 x 200 mm) when specified. The Concrete strength is calculated by dividing the maximum load at failure by the average cross sectional area.Concrete compressive strength requirements can vary from 2500 psi (17 MPa) for residential concrete to 4000 psi (28 MPa) and higher in commercial structures. Higher strengths up to and exceeding 10,000 psi (70 MPa) are specified for certain applications.Cylinders are placed in a Compression testing machine and loaded to failure from 20 to 50psi. The type of break should be recorded by a Certified Technician.Example 1:For a concrete sample that is broken after 28 daysThe cylinder is 6” diameter, so it has an area of 3.14 x Diameter squared /4A = 3.14 x 6 x 6/4A = 28.26 square inchesIf the force required to break the cylinder was 97,500 poundsThen the compressive strength is 97,500 pounds / 28.26 square inches = 3,450 psi.3,450psi needs to be compared to the Design strength determined by the Design Strength determined by the Design Engineer.Example 2:Given: f 'c = 3000 psiConcrete test cylinders averaged 2800 psi.PSICore 1 =2900Core 2 =2850Core 3 =2450Average compressive strength of 3 cores = 2730 psi.Find: Is the concrete in the structure adequate under CDOT specifications?Solution:Test Evaluation:f 'c = 3000 psiAverage compressive strength of 3 cores - 2730 psiDo any compressive strengths differ from the average by more than 10%?10% of Average compressive strength = 273 psiCore 1: 2900 - 2730 = 170 psi, < 273 therefore OKCore 2: 2850 - 2730 = 120 psi, < 273 therefore OKCore 3: 2730 - 2450 = 280 psi, > 273 therefore -discard core and re-compute average compressive strength using two remaining cores.New average compressive strength = 2875 psi
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Radius of a circle = diameter/2
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Field diameter of lens B equals field diameter of lens A times total magnification of lens A divided by total magnification of lens B
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For a hole 36" deep X 18" diameter, you would need approx. 1/5 cu. yd. concrete.
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Divide the area by Pi to get the diameter.
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Divide the area by pi (= 3.14159 approx) to get diameter.
