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Calculate the maximum wavelength of the light require to ionize a single sodium atom?
Wiki User
∙ 12y ago
Na (g)------>Na++ e-
The first ionization energy is I=495,8 kJ/mol, and for one atom the energy is:
495,8/6,02214129 = 8,235·10-19 J/atom
E=hv=hc/λ and:
λ=hc/E= (6,626 069 57·10-34 J·s)(3,00·108 m/s)/8,235.10-19 J/atom = 242 nm
Wiki User
∙ 12y ago
Wiki User
∙ 12y agoNa (g)-->Na^+^(g) + e- I=495.9kj/mol
495.9 kj/mol * 1000j/1kj * 1mol/6.022*10^23^= 8.235*10^-19^ j/atom
E=hv=hc/T---> T=HC/e= (6.63*10^-34^J.S)(3.00*10^8^M/J)
______________________________ =2.42*10^-17^
8.235*10^-19^J/ATOM =242nm
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