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HCl is a strong acid, therefore we can assume that it ionises completely into H+ (or H3O+ if you prefer) and Cl- ions.
Therefore an 0.10 M HCl solution will contain 0.10 moles/L of H+ ions.
pH = -log10[H+] where [ ] denotes "concentration of" in moles/L
Note that the formal definition of pH relies on the "activity" of H+ (which is the product of an activity coefficient and concentration), but for simple problems this can be be ignored.
So pH = -log[0.1]
= 1.0
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The pH in aqueous solution of hcl at 25c is 4 hcl0.003 moles was added to 1l of this solution calculate the new pH in the solution assume complete dissociation of hcl?
if its complete dissociation, then the products would be a salt and water, which means the pH is 7 or neutral. OMG, if the pH is currently 4 then [H+] = 1.0 e-4 M (pH = -log[H+]) if you add 0.003 moles then 1.0e-4 M +.003 M = .0031 M (Since the strong acid HCL completely dissociates in aq solution) pH = -log [.0031M] = 2.51
What is the pH of a 0.280 molar HCl solution?
pH = -log(0.280) = 0.553
Calculate the pH of a solution prepared by diluting 3.0 mL of 2.5 M HCl to a final volume of 100 mL with H2O?
Because HCl is a strong acid, it dissociates completely to H + Cl. Therefore, 3.0 mL x 2.5 M HCl = 7.5 meq of H+ . In 100 mL of solution, this is 0.075 M H+. pH= - log [H] = - log (0.075) = - (-1.1) = 1.1 (two significant figures)
What is the pH of a 4.3 x 10-2 M HCl is the solution?
p(x)=-log([x])So... pH=-log([H+])pH = 1.4
What is acidity of hydrogen chloride?
Hydrogen chloride is an acid and its acidity depends on the concentration of the solution. For example, a 0.1M solution of HCl has a pH value of 2.0
How to calculate pH of 1N HCl solution?
pH = -log10[H+], where [H+] is the hydrogen ion concentration. So, in this case, pH = -log10[1], yielding pH = 0.
The pH of a 0.01 M solution of HCl in water would be?
pH = - log[H+] so a 0.01 M solution of HCl has, pH= 2
How calculate pH for a solution?
HCl is a strong acid and dissociates completely. Therefore it can be found using the equation: ph= -log [H+]
What is the pH of a 0.001 M of HCl solution?
its PH is 3
What is the pH of a solution of 0.010 M HCl?
Its pH value is 2.
What is the pH of a 1.0x10-4m hcl solution?
- log(0.00450 M HCl)= 2.3 pH=======
The pH in aqueous solution of hcl at 25c is 4 hcl0.003 moles was added to 1l of this solution calculate the new pH in the solution assume complete dissociation of hcl?
if its complete dissociation, then the products would be a salt and water, which means the pH is 7 or neutral. OMG, if the pH is currently 4 then [H+] = 1.0 e-4 M (pH = -log[H+]) if you add 0.003 moles then 1.0e-4 M +.003 M = .0031 M (Since the strong acid HCL completely dissociates in aq solution) pH = -log [.0031M] = 2.51
What is the pH of 10.0L of 0.0020 M HCL?
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
How many moles of HCL is present in 1 liter of stomach solution that has a PH of 1?
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
Calculate the pH of 0.01m hcl?
HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2
What is the pH of a 0.280 molar HCl solution?
pH = -log(0.280) = 0.553
What is the pH of an aqueous solution of HCl with a concentration of 42m?
the pH is .377 the pH is .377
