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What is the percent by mass of oxygen in CaOH2 formula mass 74.1?
Wiki User
∙ 11y ago
Molecular mass of calcium oxide = calcium (40,078) + oxygen (15,9994) = 56,0774
56,0774 CaO--------------40,078 Ca
100 g CaO-----------------x g Ca
x = (40,078 x 100)/56,o774 = 71,469 % Ca
Wiki User
∙ 12y ago
Wiki User
∙ 7y agoIn Ca(OH)2 there is 1 Ca, 2 O, and 2H
Ca = 40 g
O = 16 x 2 = 32
H = 1 x 2 = 2
Total mass = 40 + 32+ 2 = 74 g
%O by mass = 32/74 (x100) = 43.2%
Wiki User
∙ 7y agoThe percentage composition by mass of oxygen in Ca(OH)2 is 43,24 %.
Wiki User
∙ 11y ago43.2 percent
Wiki User
∙ 14y agohahahaha wot ever u do know the answer
Wiki User
∙ 11y agohow can you get 12 percent CaO from CaCl2
Wiki User
∙ 7y agoOxygen accounts for 43.2%.
Wiki User
∙ 14y ago60%
Wiki User
∙ 12y ago142.5%
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What is the empirical formula of a compound that contains 57 percent sulfur and 43 percent oxygen by mass?
Since the atomic mass of sulfur is very close to twice the atomic mass of oxygen, the ratio of numbers of oxygen atoms to numbers of oxygen atoms is close to 43:28.5. The closest ratio of small integers is 3:2; therefore the empirical formula is S2O3.
What is the percent composition of O in LiOH?
The formula shows that oxygen is one atom out three in the formula unit, so that the atomic percent of oxygen in the compound is 33.333.......... By adding the gram atomic masses of the three elements, one obtains 23.95 as the gram formula mass, to the justified number of significant digits (the four digits in the value for the gram atomic mass of lithium), and 100 (15.9994/23.95) is 66.80 percent by mass of oxygen in LiOH.
What is the mass percent of oxygen in of N2O4?
The percent by mass of oxygen in N2O4 is 69,56 %.
What is the mass percent of oxygen in SO2?
The mass percent of oxygen in SO2 is 50 %.
What is the approximate percent by mass of oxygen in SO3?
60%
What is the empirical formula of a compound that contains 57 percent sulfur and 43 percent oxygen by mass?
Since the atomic mass of sulfur is very close to twice the atomic mass of oxygen, the ratio of numbers of oxygen atoms to numbers of oxygen atoms is close to 43:28.5. The closest ratio of small integers is 3:2; therefore the empirical formula is S2O3.
What is the percent composition of O in LiOH?
The formula shows that oxygen is one atom out three in the formula unit, so that the atomic percent of oxygen in the compound is 33.333.......... By adding the gram atomic masses of the three elements, one obtains 23.95 as the gram formula mass, to the justified number of significant digits (the four digits in the value for the gram atomic mass of lithium), and 100 (15.9994/23.95) is 66.80 percent by mass of oxygen in LiOH.
What is the formula mass of oxygen?
Oxygen formula O2
What is the mass percent of oxygen in of N2O4?
The percent by mass of oxygen in N2O4 is 69,56 %.
What is the empirical formula of a compound that is 4 percent sulfur and 6 percent oxygen by weight?
We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.
How find percent compsotion of oxygen in Na2O?
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
What is the molecular formula of a compound containing 89 percent cesium Cs and 11 percent oxygen O with a molar mass equals 298 gmol?
Cs2O2
What is the mass percent of oxygen in SO2?
The mass percent of oxygen in SO2 is 50 %.
What are the steps on finding what the mass of oxygen in a 10 g of zircon?
Well, the formula for zircon is ZrSiO4 so, this means that you need to find the molar mass of the entire thing. Once you have this you find the percent mass that oxygen takes, by dividing the mass of the oxygen by the mass of the total compound. Then you multiply this number by the 10g and voila.
What is the relative formula mass of oxygen?
Oxygen is a non meta element. Atomic mass of it is 16.
What is the percent by mass of oxygen in sb4o6?
The properly written formula is Sb4O6, showing that each unit contains 4 antimony atoms and 6 oxygen atoms. The gram atomic mass of oxygen is 15.9994 and that of antimony is 121.75. Therefore, the percent by mass of oxygen is 100{(6)(15.994)/[(4)(121.75) + (6)(15.994)} or 16.466, to the justified number of significant digits. (The integers 4 and 6 are exact).
What is the percent of oxygen by mass in a pure sample of FeCr2O4?
To determine the percentage of oxygen in FeCr2O4, you would first calculate the molar mass of the compound (iron(II) chromite) using the atomic masses of each element (Fe = 55.85 g/mol, Cr = 51.996 g/mol, O = 16 g/mol). Then, calculate the molar mass percentages of each element within the compound, and finally, determine the percentage of oxygen by mass in the compound.
