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The formula shows that oxygen is one atom out three in the formula unit, so that the atomic percent of oxygen in the compound is 33.333.......... By adding the gram atomic masses of the three elements, one obtains 23.95 as the gram formula mass, to the justified number of significant digits (the four digits in the value for the gram Atomic Mass of lithium), and 100 (15.9994/23.95) is 66.80 percent by mass of oxygen in LiOH.

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The molar mass of LiOH is 23.95 g/mol for Li, 15.999 g/mol for O, and 1.008 g/mol for H. The molar mass of LiOH is 23.95 + 15.999 + 1.008 = 40.957 g/mol. Therefore, the percent composition of Li in LiOH is (23.95/40.957) x 100 = 58.44%.


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