By Ohm's law, 120 volts across 230 ohms is 0.522 amps. By the power law, that translates to 62.6 watts. You ask about power loss. In order to answer that, you need to provide more information, such as some change in configuration, or some other component. Please review and restate your question.
Kw can be calculated from volts be using the formula p=(voltage)square/resistance*1000
Use Ohm's law. V = I * R where V is voltage in volts, I is current in amperes, and R is resistance in ohms.
I(current) = V(voltage)/R(resistence) Example : 220 V / 5000 Ohm = 0.044 A (Ampère) = 44mA
voltage is equal to resistance multiplyed by current. you have the 2 pieces of info, just multiply
By driving current through a resistance, we create heat. But it takes voltage to drive current through a resistance. In that light, it takes both voltage and current to drive a resistance heater and get it hot. Power (watts) is current (amps) times voltage (volts). But power is also current squared (I2) times resistance (ohms), or I2R. Power is also voltage squared (E2) divided by resistance (ohms) or E2/R. To increase current through a given resistance (like a resistive heating element) you have to increase the voltage. Voltage, current and resistance are "locked" in a fixed arrangement called Ohm's law. It's a relationship that takes this form: E = I x R, or I = E/R, or R = E/I As power is amps times volts (P = I x E), we can answer the question asked here. Question: "Does heat come from the amps or the volts?" Answer: "Yes."
Resistance calculations are the same no matter what the polarity of applied voltage. R=E/I Resistance (in ohms) = Voltage (in volts) divided by Current (in amperes)
Power is inversely proportional to resistance. Ohm's law: Current is voltage divided by resistance Power law: Power is voltage times current, therefore power is voltage squared divided by resistance.
Power, in 'watts'.
If the resistance is 1.2k and the current is 0.024 ma, then the voltage is 0.0288 volts. (Voltage = resistance times current) If the voltage is 0.0288V and the current is 0.024 ma, then the power is 0.6912 microwatts. (Power = voltage times current)
Voltage(volts)=Power(watts)/Current (ampheres) Or Voltage=Curren X Resistance(Ohms) -X
The question is a bit ambiguous, but I will try to address it. If the 6 ohm resistance is in series with another resistance then some of the 5 volts would be dropped across the 6 ohm resistance and the remainder of the voltage would be dropped across the other resistance. To calculate the voltage, use the 'resistor voltage divider equation' (Google it). If the 5 volts is applied across only a 6 ohm resistance, then the top of the resistor is at 5 volts and the bottom of the resistor would be at 0 volts. The resistor would drop all of the voltage.
U = RxI so 11x20=220 volts
Power (watts) = current (amperes) * voltage (volts) Current (amperes) = voltage (volts)/resistance (ohms) 120 watts = current * 120 volts current = 1 ampere 1 ampere = 120 volts/resistance resistance = 120 ohms
Kw can be calculated from volts be using the formula p=(voltage)square/resistance*1000
You need to know the resistance. Ohm's Law: Current = Voltage (in volts) divided by resistance (in ohms).
Use Ohm's law. V = I * R where V is voltage in volts, I is current in amperes, and R is resistance in ohms.
All resistances will emit heat energy when a current flows. The heat production rate (or power) can be found by any of these formulas: Power = Current * Voltage Power = Current2 * Resistance Power = Voltage2 / Resistance. Power is given in Watts when Current is in Amps, Voltage in Volts, and Resistance in Ohms.