Use Ohm's law.
V = I * R
where V is voltage in volts, I is current in amperes, and R is resistance in ohms.
I have no idea
Electrical current is measured in amperes.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
V = I*R, so take 100 volts and divide it by the value of the resistance to get the current. Current is measured in amperes.
You need to calculate the equivalent resistance. For instance, if the three resistors are connected in series, simply add all the resistance values up. Then, you calculate the current (in amperes) using Ohm's Law (V=IR); that is, you need to divide the voltage by the resistance.
Ohm's law: Voltage is resistance times current. 80 ohms time 0.5 amperes = 40 volts.
I have no idea
0.02 amperes
9 amperes.
Electrical current is measured in amperes.
It looks as if you can use Ohm's Law to calculate this: V=IR (voltage = current x resistance).
1.5 volts
2 amperes (current = voltage/resistance)
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
A resistance of 3 ohms connected between the terminals of a 9-volt battery will result in a current of 3 Amperes. If the battery is one of those little ones with snaps on top, it may be able to produce 3 amperes of current for about 3 seconds before it rolls over and totally dies.
Resistance calculations are the same no matter what the polarity of applied voltage. R=E/I Resistance (in ohms) = Voltage (in volts) divided by Current (in amperes)
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