I have no idea
Use Ohm's law. V = I * R where V is voltage in volts, I is current in amperes, and R is resistance in ohms.
Electrical current is measured in amperes.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
If 3 identical 45-ohm resistors are connected in parallel, the net effective resistance of the bunch ...and the load seen by the battery ... is 15 ohms. The current supplied by the battery is60/15 = 4 Amperes.(This assumes that the battery is capable of supplying 4 amps at 60 volts, or 240 watts !)
Your current will be 30/R Amps. Where R is the resistance in Ohms.
A resistance of 3 ohms connected between the terminals of a 9-volt battery will result in a current of 3 Amperes. If the battery is one of those little ones with snaps on top, it may be able to produce 3 amperes of current for about 3 seconds before it rolls over and totally dies.
Use Ohm's law. V = I * R where V is voltage in volts, I is current in amperes, and R is resistance in ohms.
That will depend on the sum of the load resistance and the internal resistance of the battery (this is true for all power sources, not just 6 volt batteries). Small compact batteries tend to have higher internal resistance and therefore are more limited in the current they can deliver to a given load than larger batteries.
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes. If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
Electrical current is measured in amperes.
3 amperes. Ohm's law: Voltage is ohms times amperes.
That depends on the resistance connected. Use Ohm's Law: V=IR. Solving for current: I = V/R. If nothing is connected, there will be no current (infinite resistance).
1.5 volts
2 amperes (current = voltage/resistance)
The current depends on what is connected to the battery's terminals. If nothing is connected to it, then there is no current, and the battery lasts quite a while. In general, the current is 1.5/resistance of the external circuit connected to the battery until that number gets too big, and then the voltage of the battery sags, because it can't deliver that much current.
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
Ohm's law: Voltage is resistance times current. 80 ohms time 0.5 amperes = 40 volts.