1.5 volts
10
Ohm's Law: Current = Voltage divided by resistance 9 volts divided by 3 ohms = 3 amperes.
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the resistor is the only component there, then the current is E/R = 12/3 = 4 amperes.
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes. If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
If the two 5 ohm resistors were in series, then the current would be 1.2 amperes. If they were in parallel, then the current would be 4.8 amperes. Ohm's Law: Current = Voltage divided by Resistance RSeries = Summation1toN RN RPARALLEL = 1 / Summation1toN (1 / RN)
2 amperes (current = voltage/resistance)
10
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
A resistance of 3 ohms connected between the terminals of a 9-volt battery will result in a current of 3 Amperes. If the battery is one of those little ones with snaps on top, it may be able to produce 3 amperes of current for about 3 seconds before it rolls over and totally dies.
Use Ohm's law. V = I * R where V is voltage in volts, I is current in amperes, and R is resistance in ohms.
I have no idea
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the bulb is the only component there, then the current is E/R = 9/12 = 0.75 amperes.
Ohm's Law: Current = Voltage divided by resistance 9 volts divided by 3 ohms = 3 amperes.
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
Six amperes. Use Ohm's law: the current is the voltage divided by the resistance
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.